Posts by Habeeb

Total # Posts: 3

two forces each of magnitude 10newton act in opposite direction at the end of the table if the length of the table is 50centimeter calculate.The resultant force and moment acting on the table.

A ball of mass 0.3kg moving at a velocity 20/s is suddenly hit by a force of 5 Newton for a time of 0.03 seconds. Find its new velocity

Friction = uN N=mg so F=umg F at t(0) = (.505)(4.17 kg)(9.8 m/s^2) F at t>0 = (.255)(4.17 kg)(9.8 m/s^2)

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