# Posts by Bosnian

Total # Posts: 2,513

**math**

( 4 / 7 ) x = - 16 Multiply both sides by 7 4 x = - 16 * 7 4 x = - 112 Divide both sides by 4 x = - 112 / 4 = - 28 Answer B 4 s + 13 + s = 2 s + 40 - 6 5 s + 13 = 2 s + 34 Subtract 2 s to both sides 5 s + 13 - 2 s = 2 s + 34 - 2 s 3 s + 13 = 34 Subtract 13 to both sides 3 s + ...

**Math**

0.67 = 67 / 100 0.3 = 3 / 10 0.67 * 0.3 = 67 / 100 * 3 / 10 = 67 * 3 / ( 100 * 10 ) = 201 / 1000 = 0.201

**mystery number math please help**

The digit in the hundreds place is 3 times greater than the digit in the ones place. The digit in the ones place is 6 less than the digit in the hundred thousands place. If you mark digit in the one place with x and digit in the hundreds place with h this mean: h = 3 x and x...

**Math**

a = larger number b = smaller number The difference of two number is seven mean: a - b = 7 a - b = 7 Add b to both sides a - b + b = 7 + b a = 7 + b a = b + 7 When the larger number is decreased by five, then doubled, it is five more than the small number mean: ( a - 5 ) * 2...

**Math**

Your answer is partially correct. 4 ( 9 + 6 ) = 4 * 15 = 60 But also: 36 = 12 * 3 24 = 12 * 2 36 + 24 = 12 * 3 + 12 * 2 = 12 ( 3 + 2 ) 12 * ( 3 + 2 ) = 12 * 5 = 60 Answers b and d

**MATH**

If the initial term of an arithmetic progression is a a1 and the common difference of successive members is d, then the nth term of the AP is given by: an = a1 + ( n - 1 ) d a4 = a1 + ( 4 - 1 ) d a4 = a1 + 3 d = - 3 a9 = a1 + ( 9 - 1 ) d a9 = a1 + 8 d = 12 Now you must solve ...

**maths**

a / b = 3 / 4 Multiply both sides by b a = ( 3 / 4 ) b a + b = 84 ( 3 / 4 ) b + b = 84 ( 3 / 4 ) b + ( 4 / 4 ) b = 84 ( 7 / 4 ) b = 84 Multiply both sides by 4 7 b = 84 * 4 7 b = 336 Divide both sides by 7 b = 336 / 7 = 48 b = 48 a = ( 3 / 4 ) b = 3 * 48 / 4 = 144 / 4 = 36 a...

**maths**

a / b = 2 / 3 Multiply both sides by b a = ( 2 / 3 ) b a + b = 30 ( 2 / 3 ) b + b = 30 ( 2 / 3 ) b + ( 3 / 3 ) b = 30 ( 5 / 3 ) b = 30 Multiply both sides by 3 5 b = 30 * 3 5 b = 90 Divide both sides by 5 b = 90 / 5 = 18 a = ( 2 / 3 ) b = 2 * 18 / 3 = 36 / 3 = 12 a / b = 12 / ...

**math 115**

Reiny Volume isn't (100)(290)(29) km^3 a river is 100 kilometers long 290 meters wide and 29 meters deep 1 km = 1000 m 1 m = 1 / 1000 m 290 m = 290 / 1000 = 0.29 km 29 m = 29 / 1000 = 0.029 km Volume = ( 100 * 0.29 * 0.029 ) km ^ 3 = 0.841 km ^ 3 = 8.41 * 10 ^ - 1 km ^ 3

**math 115**

1 m = 10 dm 1 km = 1,000 m = 10,000 dm 100 km * 290 m * 29 m = 100 * 10,000 dm * 290 * 10 dm * 29 * 10 dm = ( 1,000,000 * 2,900 * 290 ) dm ^ 3 = ( 10 ^ 6 * 2.9 * 10 ^ 3 * 2.9 * 10 ^ 2 ) dm ^ 3 = ( 10 ^ 6 * 10 ^ 3 * 10 ^ 2 ) * ( 2.9 * 2.9 ) dm ^ 3 = ( 10 ^ 11 * 2.9 ^ 2 ) dm ^ 3...

**Math (Trig Review)**

tan ( arctan x ) = x cot x = 1 / tan x tan ( arccot x ) = tan [ arc (1 / tan x ) ] = 1 / tan ( arctan x ) = 1 / x tan ( arccot 2 ) = tan [ arc (1 / tan 2 ) ] = 1 / tan ( arctan 2 ) = 1 / 2

**math**

4 ( x + 3 ) = 5 x - 2 4 * x + 4 * 3 = 5 x - 2 4 x + 12 = 5 x - 2 Subtract 4 x to both sides 4 x + 12 - 4 x = 5 x - 4 x - 2 12 = x - 2 Add 2 to both sides 12 + 2 = x - 2 + 2 14 = x x = 14

**Math**

S = Sheila´s money R = Rita´s money Sheila and Rita had $300 mean: S + R = 300 S + R = 300 Subtract S to both sides S + R - S = 300 - S R = 300 - S After Shiela gave $56 to Rita, Shiela had: S - 56 dollars Rita had: R + 56 = 300 - S + 56 = 356 - S Rita had 5 times ...

**carson high school**

5 r - 3 s = 19 Multiply both sides by - 2 5 r * ( - 2 ) - 3 s * ( - 2 ) = 19 * ( - 2 ) - 10 r + 6 s = - 38

**carson high school**

5 r - 3 s = 19 Multiply both sides by - 2 - 5 r * ( - 2 ) - 3 s * ( - 2 ) = 19 * ( - 2 ) - 10 r + 6 s = - 38 Now your system become: - 10 r + 6 s = - 38 + 2 r - 6 s = - 2 __________________ - 10 r + 2 r + 6 s - 6 s = - 38 + ( - 2 ) - 8 r = - 38 - 2 - 8 r = - 40 Divide both ...

**Algabra**

D = Dick's age T = Tom's age H = Harry's age M = Mother's age D < T D > H D = T - 2 Add 2 to both sides D + 2 = T - 2 + 2 D + 2 = T T = D + 2 M = 3 D also: M = 2 T + 13 = 2 ( D + 2 ) + 13 = 2 * D + 2 * 2 + 13 = 2 D + 4 + 13 = 2 D + 17 M = M 3 D = 2 D + 17...

**Algebra**

6 = 6 * 3 / 3 = 18 / 3 6 = x + 2 / 3 18 / 3 = x + 2 / 3 Subtract 2 / 3 to both sides 18 / 3 - 2 / 3 = x + 2 / 3 - 2 / 3 16 / 3 = x x = 16 / 3

**Math**

1 / 2 = 1 * 4 / ( 2 * 4 ) = 4 / 8 1 / 2 + 3 / 8 = 4 / 8 + 3 / 8 = 7 / 8

**Matrices**

In google type: 2x2 System of Equations - Solver that Shows Steps When you see list of results clik on: 2x2 System of Equations - Solver that Shows Steps - Math Lessons When page be open type your coefficients: 3 , - 9 , 30 and 2 , 5 , -2 Click on: Solve by using Cramer's ...

**Maths - Ratio**

A = Angelique's ages S = Serena’s ages V = Venus’ ages A / S = 5 / 3 S / V = 6 / 5 Angelique is 25 years older than Venus mean: A = V + 25 Replace this value in equation: A / S = 5 / 3 ( V + 25 ) / S = 5 / 3 Multiply both sides by S V + 25 = 5 S / 3 Multiply both...

**Pre algebra**

Replace s = 4 and t = 8 in your equation. 2 s t ^ 2 - s ^ 2 = 2 * 4 * 8 ^ 2 - 4 ^ 2 = 2 * 4 * 64 - 16 = 8 * 64 - 16 = 512 - 16 = 496

**Math HELP!**

3 / 4 = 0.75 - 5 / 6 = - 0.833 0.75 > - 0.833 3 / 4 > - 5 / 6 - 1 3/4 = - 1.75 3 / 4 = 0.75 - 1.75 < 0.75 - 1 3/4 < 3 / 4 2 3/4 = 2.75 2 4/6 = 2 2/3 = 2.666 2.75 > 2.666 2 3/4 > 2 4/6

**maths**

A = P ( 1 + r / n ) ^ ( n * t ) A = total amount P = principal or amount of money deposited, r = annual interest rate n = number of times compounded per year t = time in years In this case : P = 224000 R = 2 % = 2 / 100 = 0.02 n = 1 t = 16 A = P ( 1 + r / n ) ^ ( n * t ) A = P...

**geometry**

Area of a regular hexagon = [ 3 sqroot ( 3 ) / 2 ] * a ^ 2 Where, a is the side of the hexagon. A = [ 3 sqroot ( 3 ) / 2 ] * a ^ 2 A = [ 3 sqroot ( 3 ) / 2 ] * 4 ^ 2 A = [ 3 sqroot ( 3 ) / 2 ] * 16 A = [ 3 sqroot ( 3 ) / 2 ] * 2 * 8 A = 3 sqroot ( 3 ) * 8 A = 24 sqroot ( 3 ) ...

**math**

If your expression mean: ( 3.96 x 10 ^ 2 ) / ( 1.5 x 10 ^ 6 ) then: 3.96 x 10 ^ 2 / 1.5 x 10 ^ 6 = ( 3.96 / 1.5 ) * ( 10 ^ 2 / 10 ^ 6 ) = 2.64 x 10 ^ ( 2 - 6 ) = 2.64 x 10 ^ -4

**math**

15 2/6 = 15 + 2 / 6 = 15 * 6 / 6 + 2 / 6 = 90 / 6 + 2 / 6 = 92 / 6 Multiply both sides by 4 4 * 92 / ( 4 * 6 ) = 368 / 24 15 2/6 = 368 / 24 9 1/4 = 9 + 1 / 4 = 9 * 4 / 4 + 1 / 4 = 36 / 4 + 1 / 4 = 37 / 4 Multiply both sides by 6 6 * 37 / ( 6 * 4 ) = 222 / 24 9 1/4 = 222 / 24 ...

**Maths**

A = b * h / 2 = [ ( 11 / 2 ) * ( 7 / 3 ) ] / 2 = ( 77 / 6 ) / 2 = 77 / 12

**Math**

17 - 2 * 3 - 8 = 3 17 - 6 - 8 = 11 - 8 = 3 33 / 3 - 2 * 5 = 1 11 - 10 = 1

**math**

( 1 + x + x ^ 2 ) ^ 3 = [ ( 1 + x ) + x ^ 2 ] ^ 3 Now use formulas: ( a + b ) ^ 2 = a ^ 2 + 2 a b + b ^ 2 and ( a + b ) ^ 3 = a ^ 3 + 3 a ^ 2 * b + 3 a * b ^ 2 + b ^ 3 [ ( 1 + x ) + x ^ 2 ] ^ 3 = ( 1 + x ) ^ 3 + 3 ( 1 + x ) ^ 2 * x ^ 2 + 3 ( 1 + x ) * ( x ^ 2 ) ^ 2 + ( x ^ 2...

**Urgent Math**

OR cot ( 2x ) - csc ( 2x ) = cos ( 2x ) / sin ( 2x ) - 1 / sin ( 2x ) = [ cos ( 2x ) - 1 ) ] / sin ( 2x ) Since the: cos ( 2x ) = cos ^ 2 x - sin ^ 2 x sin ( 2 x ) = 2 sin x cos x you can write: cot ( 2x ) - csc ( 2x ) = ( cos ^ 2 x - sin ^ 2 x - 1 ) / 2 sin x cos x = [ ( - 1...

**Math**

210,004,050

**algebra**

l = length w = width P = perimeter l = 2 w P = 2 ( l + w ) = 126 2 ( 2 w + w ) = 126 2 * 3 w = 126 6 w = 126 w = 126 / 6 = 21 ft l = 2 w = 2 * 21 = 42 ft

**Math**

A = b * h / 2 14 = 4 * h / 2 14 = 2 h h = 14 / 2 = 7

**Math**

g = the greater part s = the smaller part 2 g = 3 s Divide both sides by 2 g = ( 3 / 2 ) s g + s = 75 ( 3 / 2 ) s + s = 75 ( 3 / 2 ) s + ( 2 / 2 ) s = 75 ( 5 / 2 ) s = 75 Multiply both sides by 2 5 s = 75 * 2 5 s = 150 Divide both sides by 5 s = 150 / 5 s = 30 g = ( 3 / 2 ) s ...

**CGTC**

9 % = 9 / 100 = 0.09 7 % = 7 / 100 =0.07 x = the amount of money $100 less then three times the amount = 3 x - 100 x * 0.09 + ( 3 x - 100 ) * 0.07 = 83 0.09 x + 3 x * 0.07 - 100 * 0.07 = 83 0.09 x + 0.21 x - 7 = 83 0.3 x - 7 = 83 0.3 x = 83 + 7 0.3 x = 90 x = 90 / 0.3 x = 300 ...

**Math**

"Prime Factorization" is finding which prime numbers multiply together to make the original number. In this case: 6 = 2 * 3 = 2 ^ 1 * 3 ^ 1 9 = 3 ^ 2 15 = 3 * 5 = 3 ^ 1 * 5 ^ 1 The highest power of the three prime numbers 2, 3, and 5 is: 2 ^ 1 = 2 3 ^ 2 = 9 5 ^ 1 = 5...

**Math**

1 * 300,000 / 10 = 300,000 / 10 = 30,000

**Math**

V = A * h 7,168 = 521 h Divide both sides by 512 7,168 / 512 = h 14 = h h = 14 cm

**Math**

|- 8| = 8 - 6 < |- 8| -6 < 8 Answer B

**pre calculus honors**

x + y + z = 15 7 x + y + z = 75 3 x + y - z = 29 Multiply first equation by − 7 ( x + y + z = 15 ) * ( - 7 ) -7 x - 7 y - 7 z = - 105 add this to the second equation -7 x - 7 y - 7 z = - 105 + 7 x + y + z = 75 ____________________ The result is: - 6 y - 6 z = - 30 Divide...

**math**

Yes

**Math**

( x + 1 ) * 500500 = 500500 ( x + 1 )

**Math**

If you in google type: Sum of numbers 1 to 100 By the way: 1 + 2 + 3 + 4 + . . . . + n = ( 1 + n )*( n / 2 ) 1 + 2 + 3 +…100 n = 100 1 + 2 + 3 +…100 =( 1 + 100 ) * ( 100 / 2 ) = 101 * 50 = 5050 ( x + 1 ) + 2 ( x + 1) + …+ 1000 ( x + 1 ) = ( x + 1 ) ( 1 + 2 +......

**Math**

This is calculus problem. In an open box you have square base with area a ^ 2 and 4 rectangle with area a * h where a is length of base and h is height of box Area of an open box: A = a ^ 2 + 4 a * h A = a ^ 2 + 4 a * h = 24 Subtract a ^ 2 to both sides a ^ 2 + 4 a * h - a ^ 2...

**Math**

22 - 10 = 12 34 - 22 = 12 46 - 34 = 12 58 - 46 = 13 70 - 58 = 12 Missing number = 70

**math**

25 = 5 * 5 35 = 5 * 7 1.25 = 5 / 4 25 / 35 = 1.25 / x become: 5 * 5 / ( 5 * 7 ) = 5 / 4x 5 / 7 = 5 / 4x Divide both sides by 5 1 / 7 = 1 / 4x Multiply both sides by x x / 7 = 1 / 4 Multiply both sides by 7 x = 7 / 4 = 1.75

**Maths**

16 baqgs * 1.5 kg = 24 kg $672 / 24 kg = $28 / kg 18 bags * 2 kg = 36 kg 36 kg * $28 / kg = $ 1,008 OR 16 * 1.5 / ( 18 * 2 ) = 672 / x 24 / 36 = 672 / x 2 * 12 / ( 3 * 12 ) = 672 / x 2 / 3 = 672 / x 2 * x = 3 * 672 2 x = 2,016 x = 2,016 / 2 x = $ 1,008

**math**

625 = 25 * 25 ã625 = 25 sqroot ( ã625 ) = sqroot ( 25 ) = 5

**Algebra**

-5 > -8 Draw a number line: 0, - 1, - 2, - 3, - 4 , - 5, - 6 , - 7, - 8, - 9...

**math**

In your case x and y coordinates are: x1 = 0, x2 = 2, x3 = 4, x4 = 6 y1 = - 3, y2 = - 2, y3 = -1, y4 = 0 slope = change in y / change in x This mean, divide the change in height by the change in horizontal distance. slope = ( y2 - y1 ) / ( x2 - x1 ) = [ - 2 - ( - 3 ) ] / ( 2...

**maths**

Sum of a certain number of terms of an arithmetic sequence: Sn = n ( a1 + an ) / 2 In this case: S9 = 9 ( a1 + a9 ) / 2 = 279 S20 = 20 ( a1 + a20 ) / 2 = 1280 9 ( a1 + a9 ) / 2 = 279 Multiply both sides by 2 9 ( a1 + a9 ) = 279 * 2 9 a1 + 9 a9 = 558 On the other side: an = a1...

**math**

Replace 2 instead p in your equation. ( 34 + 18 p ) - ( 5 + p ) = ( 34 + 18 * 2 ) - ( 5 + 2 ) = 34 + 36 - 7 = 70 - 7 = 63

**math**

A perfect square is a number that can be expressed as the product of two equal integers. 169 = 13 * 13 A perfect cube is a number that can be expressed as the product of three equal integers. 169 = 5.5287748 * 5.5287748 * 5.5287748 5.5287748 isn't whole number so 169 is a ...

**math**

100.1 % = 100.1 / 100 ( 100.1 / 100 ) * ( 10 / 10 ) = 1001 / 1000 100.1 % = 1001 / 1000

**Algebra**

60 * 4 / 5 = 240 / 5 = 48 48 students are members of Math Club. Among the members, 3 / 5 are girls: 48 * 3 / 5 = 144 / 5 = 28.8 girls 48 - 28.8 = 19.2 boys Your question does not make sense.

**math**

S = Present Sam's age B = Present brother's age Sam is one-third as old as his brother mean: S = B / 3 After six year Sam will be S + 6 years od. Brother will be B + 6 years old. In six years Sam will be one-half as old mean: ( S + 6 ) / ( B + 6 ) = 1 / 2 Now you must ...

**Maths**

a + b = 14 a * b = 40 a + b = 14 Subtract a to both sides a + b - a = 14 - a b = 14 - a a * b = 40 a * ( 14 - a ) = 40 14 a - a ^ 2 = 40 - a ^ 2 + 14 a = 40 Subtract 40 to both sides - a ^ 2 + 14 a - 40 = 40 - 40 - a ^ 2 + 14 a - 40 = 0 Multiply both sides by - 1 a ^ 2 - 14 a...

**math**

a1 + a2 + a3 + a4 + a5 = 44 The sum of a certain number of terms of a geometric sequence: Sn = a1 * ( 1 - r ^ n ) / ( 1 - r ) In this case you have 5 terms: a1 + a2 + a3 + a4 + a5 = 44 S5 = a1 * ( 1 - r ^ 5 ) / ( 1 - r ) = 44 a1 * ( 1 - r ^ 5 ) / ( 1 - r ) = 44 The sum of the ...

**Precalculus**

sin u = 4 / 5 cos u = sqroot ( 1 - sin ^ 2 u ) cos u = sqroot [ 1 - ( 4 / 5 ) ^ 2 ] cos u = sqroot ( 1 - 16 / 25 ) cos u = sqroot ( 25 / 25 - 16 / 25 ) cos u = sqroot ( 9 / 25 ) cos u = ± 3 / 5 In Quadrant II cos is negative so: cos u = - 3 / 5 sin v = - 12 /13 cos v = ...

**Math**

L = 2 W P = 2 L + 2 W = 2 ( L + W ) P = 54 2 ( L + W ) = 54 Divide both sides by 2 L * W = 54 / 2 L + W = 27 Replace L = 2 W in this equation. 2 W + W = 27 3 W = 27 Divide both sides by 3 W = 27 / 3 W = 9 m L = 2 W = 2 * 9 = 18 m Proof: P = 2 ( L + W ) = 2 ( 18 + 9 ) = 2 * 27...

**pre cal**

sin u = 1 / 3 cos u = sqroot [ 1 - sin u ) ^ 2 ] sqroot [ 1 - ( 1 / 3 ) ^ 2 ] = sqroot ( 1 - 1 / 9 ) = sqroot ( 9 / 9 - 1 / 9 ) = sqroot ( 8 / 9 ) = sqroot ( 4 * 2 / 9 ) = sqroot ( 4 / 9 ) * sqroot ( 2 ) = + OR - ( 2 / 3 ) * sqroot ( 2 ) cos u = + OR - 2 sqrt ( 2 ) / 3 sin v...

**pre algebra**

L = larger numbr S = smaller number The difference between two numbers is 44 mean: L - S = 44 Five times the smaller is equal to 8 more than the larger mean: 5 S = L + 8 Now youust solve sytem of two equation with two unknow. L - S = 44 5 S = L + 8 L - S = 44 Add S to both ...

**Math**

4*15-11+8-2=20 ______________________ 4*1(5-1)-1(+8/-2)= 4 * 1 * 4 - 1 * ( - 4 ) = 16 + 4 = 20

**Maths**

1st term: n = 1 Sn = 3 n - 2 S1 = 3 * 1 - 2 = 3 - 2 = 1 3rd term: n = 3 Sn = 3 n - 2 S3 = 3 * 3 - 2 = 9 - 2 = 7 5th term: n = 5 Sn = 3 n - 2 S5 = 3 * 5 - 2 = 15 - 2 = 13

**pre cal**

A cubic function is a function of the form: f ( x ) = a ^ 3 + b x ^ 2 + c x + d You must find 4 coefficients: a , b , c , and d You now zero pionts: x = - 5 , y = 0 x = 2 , y = 0 and x = 4 , y = 0 You also know : f ( - 10 ) = - 4 Now put this values in equation: f ( x ) = a x...

**Math**

12 * 20 = 240

**Math**

n = 2 didit number a = tens b = ones So: n = 10 a + b The number exceeds the sum of digits by18 mean: n = a + b + 18 Now equalize exspressions for n. n = n 10 a + b = a + b + 18 Subtract b to both sides 10 a + b - b = a + b + 18 - b 10 a = a + 18 Subtract a to both sides 10 a...

**math**

3 / 7 = 15 / x Multiply both sides by x 3 x / 7 = 15 Multiply both sides by 7 3 x = 15 * 7 3 x = 105 Divide both sides by 3 x = 105 / 3 x = 35 3 / 7 = 15 / 35

**math**

1 h 45 min = 60 min + 45 min = 105 min 24 / 105 = 64 / x Muultiply both sides bx x 24 x / 105 = 64 Multiply both sides by 105 24 x = 64 * 105 24 x = 6720 Divide both sides by 24 x = 6720 / 24 = 280 min x = 240 min + 40 min = 4 * 60 min + 40 min = 4 h 40 min OR 64 / 24 = 8 * 8...

**Math**

a) 13 , 17 , 25 , 27 , 28 , x , 32 , 36 , 37 , 40 , y , 47 The median is the middle number. But there is no "middle" number, because there are an even number of numbers. In this case, the median is the mean (the usual average) of the middle two values: The median...

**math**

x = present age In five years time thabo will be three times as old as he was nine years ago, mean: 5 + x = 3 ( x - 9 ) 5 + x = 3 x - 27 Subtract x to both sides 5 + x - x = 3 x - 27 - x 5 = 2 x - 27 Add 27 to both sides 5 + 27 = 2 x - 27 + 27 32 = 2 x Divide both sides by 2 ...

**Math**

x ^ - 1/4 = 4 ^ -1/2 mean: 1 / fourth root of x = 1 / square root of 4 1 / fourth root of x = 1 / 2 Taking reciprocial of both sides: fourth root of x = 2 Rise both sides to the power of four x = 2 ^ 4 x = 16 q^ 1/2 = x mean : square root of q = x Rise both sides to the power ...

**Math**

c and d are positive consecutive odd integers mean : c = d + 2 becouse : if d are odd integers, next integer are d + 2 So: c + d = 240 d + d + 2 = 240 2 d + 2 = 240 Subtract 2 to both sides 2 d + 2 - 2 = 240 - 2 2 d = 238 Divide both sides by2 d = 238 / 2 = 119 c = d + 2 c = ...

**Math**

| a - 2 | = 9 a - 2 = + OR - 9 1 solution: a - 2 = 9 Add 2 to both sides a - 2 + 2 = 9 + 2 a = 11 2 solution: a - 2 = - 9 Add 2 to both sides a - 2 + 2 = - 9 + 2 a = - 7 | w - 1 | = 6 w - 1 = + OR - 6 1 solution: w - 1 = 6 Add 1 to both sides w - 1 = 6 + 1 w = 7 2 solution: w...

**Math**

first number: a second number: a + 1 third number: a + 2 fourth number: a + 3 fifth number: a + 4 a + a + 1 + a + 2 + a + 3 + a + 4 = 80 5 a + 10 = 80 Subtract 10 to both sides 5 a + 10 - 10 = 80 - 10 5 a = 70 Divide both sides by 5 a = 70 / 5 = 14 The numbers : 14, 15, 16, 17...

**math**

g = the greater angle s = the smaller angle = g / 2 The sum of the angles in a triangle is 180 ° 60 ° + g + s = 180 ° 60 ° + g / 2 + g = 180 ° 60 ° + g / 2 + 2 g / 2 = 180 ° 60 ° + 3 g / 2 = 180 ° Subtract 60 ° to both sides 3 g / 2 = ...

**math**

cos ^ 2 A = 1 - sin ^ 2 A cos ^ 6 A + sin ^ 6 A = ( 1 - sin ^ 2 A ) ^ 3 + ( sin ^ 2 A ) ^ 3 = _________________________________Remark : ( a - b ) ^ 3 = a ^ 3 - 3 a ^ 2 b + 3 a b ^ 2 - b ^ 3 In case ( 1 - sin ^ 2 A ) ^ 3 a = 1, b = sin ^ 2 A so : ...

**math**

S = number of students g = number of girls b = number of boys b = g + 17 S = g + b S = g + g + 17 S = 2 g + 17 g = 4 / 9 S so : S = 2 * ( 4 / 9 ) S + 17 S = ( 8 / 9 ) S + 17 Subtract ( 8 / 9 ) S to both sides S - ( 8 / 9 ) S = ( 8 / 9 ) S + 17 - ( 8 / 9 ) S ( 9 / 9 ) S - ( 8...

**Pre-Cal**

Use Trigonometric Identities : sin ( x / 2 ) = + OR - sqroot [ ( 1 - cos x ) / 2 ] cos ( x / 2 ) = + OR - sqroot [ ( 1 + cos x ) / 2 ] 0° < x < 90° meen x lies in Quadrant I In Quadrant I sin x and cos x are positive so : sin ( x / 2 ) = sqroot [ ( 1 - cos x ) / ...

**math**

30 = 8 * sqroot ( h - 40 ) Divide both sides by 8 30 / 8 = sqroot ( h - 40 ) 2 * 15 / ( 2 * 4 ) = sqroot ( h - 40 ) 15 / 4 = sqroot ( h - 40 ) Raise both sides to the power of two : ( 15 / 4 ) ^ 2 = h - 40 225 / 16 = h - 40 Add 40 to both sides 225 / 16 + 40 = h - 40 + 40 225...

**math**

3 x / 4 - 16 = 44 Add 16 to both sides 3 x / 4 - 16 + 16 = 44 + 16 3 x / 4 = 60 Multiply both sides by 4 3 x = 240 Divide both sides by 3 x = 240 / 3 x = 80 Proof : 3 * 80 / 4 - 16 = 240 / 4 - 16 = 60 - 16 = 44

**Mathematics**

P ( x ) = x ^ 3 + 2 x ^ 2 - 11 x - 12 This is a polynomial of degree 3. To find zeros for polynomials of degree 3 or higher we use Rational root test. The Rational Root Theorem tells you that if the polynomial has a rational zero then it must be a fraction p / q, where p is a ...

**math**

W / L = 60 / 80 = 20 * 3 / 20 * 4 = 3 / 4

**Math**

A = Ama's ages K = Karla's ages D = Daniel's ages Ama is 3 years older than Karla this mean : A = K + 3 Daniel is 2 years older than Ama this mean : D = A + 2 The sum of their ages is 32 this mean : A + K + D = 32 Now you have 3 equatios : A = K + 3 D = A + 2 A + K...

**Math**

x = 10% = 10 / 100 = 0.1 10% acid solution of 40 mL = 0.1 * 40 mL = 4 mL of acid Volume of new acid solution = 40 mL + x where x = volume of added wather 4 mL represent 4 % 4 % = 4 / 100 = 0.04 Now 4 mL of acid / new volume = 4 % =0.04 4 mL / ( 40 mL + x ) = 0.04 In ...

**Math**

4 3 / 5 = 4 + 3 / 5 = 4 * 5 / 5 + 3 / 5 = 20 / 5 + 3 / 5 = 23 / 5 ( 2 / 3 ) / 4 3 / 5 = ( 2 / 3 ) / ( 23 / 5 ) = 2 * 5 / ( 3 * 23 ) = 10 / 69 pounds

**math**

3 ( x - 2 ) ^ 2 - 12 = 0 Divide both sides by 3 3 ( x - 2 ) ^ 2 / 3 - 12 / 3 = 0 / 3 ( x - 2 ) ^ 2 - 4 = 0 Add 4 to both sides ( x - 2 ) ^ 2 - 4 + 4 = 0 + 4 ( x - 2 ) ^ 2 = 4 Take square root of both sides x - 2 = + OR - sqroot ( 4 ) x - 2 = + OR - 2 1 solution : x - 2 = - 2 ...

**algebra**

Yes. ( x + c ) ^ 2 = x ^ 2 + 2 * x * c + c ^ 2 In this case : 2 x c = 14 x Divide both sides bny 2 x 2 x c / 2 x = 14 x / 2 x c = 7 So : ( x + c ) ^ 2 = x ^ 2 + 2 * x * c + c ^ 2 ( x + 7 ) ^ 2 = x ^ 2 + 2 x * 7 + 7 ^ 2 = x ^ 2 + 14 x + 49

**algebra 1**

x ^ 8 * 2 y ^ 10 * 5 x ^ 5 = 2 * 5 * x ^ 8 * x ^ 5 * y ^ 10 = 10 x ^ ( 8 + 5 ) * y ^ 10 = 10 x ^ 13 y ^ 10

**Algebra**

f ( x ) = - x ^ 2 + 5 x + 4 f ( 3 ) = - 3 ^ 2 + 5 * 3 + 4 = - 9 + 15 + 4 = 10 f ( 5 ) = - 5 ^ 2 + 5 * 5 + 4 = - 25 + 25 + 4 = 4 The average rate of change : [ f ( 5 ) - f ( 3 ) ] / ( 5 - 3 ) = ( 10 - 4 ) / ( 5 - 3 ) = 6 / 2 = 3 Answer A

**Maths (Need Help)**

If y^2-1/4y=0 mean : y ^ 2 - ( 1 / 4 ) y = 0 then : Write y ^ 2 like : 4 y ^ 2 / 4 Now : 4 y ^ 2 / 4 - ( 1 / 4 ) y = 0 ( 1 / 4 ) 4 y - ( 1 / 4 ) y = 0 ( 1 / 4 ) ( 4 y ^ 2 - y ) = 0 ( 1 / 4 ) y ( 4 y - 1 ) = 0 Now you must solwe two equations : ( 1 / 4 ) y = 0 and 4 y - 1 = 0...

**math**

Go on : calc101.c o m When page be open click option : derivative then in rectangle Take the derivative of type : sin[cos[x^2]] and click option : DO IT You will see solution step by step.

**Math**

d = Diameter P = Perimeter P = d * pi = 14 * pi 4 P = 4 * 14 * pi = 56 pi = 56 * 3.14159 = 175.92904 in approx. 176 in

**Math**

Now Rony is 16 years old Sister is 16 / 4 = 4 years old After x years Rony will be 16 + x yeras old Sister will be 4 + x years old Now you must solve equation : ( 16 + x ) / ( 4 + x ) = 2 Multiply both sides by 4 + x 16 + x = 2 ( 4 + x ) 16 + x = 8 + 2 x Subtract 8 to both ...

**Algebra**

c = children a = adults 2200 people enter the zoo mean : c + a = 2200 $4,550.00 is collected mean : 1.5 c + 4 a = 4550 Now you must solve system: c + a = 2200 1.5 c + 4 a = 4550 c + a = 2200 Subtract c to both sides c + a - c = 2200 - c a = 2200 - c 1.5 c + 4 a = 4550 1.5 c + ...

**Algebra**

x = 70% alcohol solution y = 30% alcohol solution 120 L of a 45% solution have : 120 * 0.45 = 54 L alcohol Now you must solve system : 0.7 x + 0.3 y = 54 x + y = 120 The solutions are : x = 45 L , y = 75 L Proof : 0.7 * 45 + 0.3 * 75 = 31.5 + 22.5 = 54 L x + y = 45 + 75 = 120 L

**5th grade math**

1 ft = 12 in 60 / 12 = 5 ft

**Algebra**

Correct answer. ( a + b ) ^ 2 = a ^ 2 + 2 a b + b ^ 2 In this case : a = 1 2 a b = 9 2 * 1 * b = 9 2 b = 9 Divide both sides by 2 b = 9 / 2 c = b ^ 2 = ( 9 / 2 ) ^ 2 = 81 / 4 ( x + 9 / 2 ) ^ 2 = x ^ 2 + 9 x + ( 81 / 4 )

**Maths**

y = the width L = the length A = the area of original rectangle A = y * L = 140 y * L = 140 Divide both sides by y L = 140 / y New area : ( y - 2 ) ( L + 3 ) = 136 ( y - 2 ) ( 140 / y + 3 ) = 136 y * 140 / y - 2 * 140 / y + 3 * y - 3 * 2 = 136 140 - 280 / y + 3 y - 6 = 136 - ...

**Algebra**

( 1 / 2 ) ( k - 5 ) = 3 Multiply both sides by 2 k - 5 = 6 Add 5 to both sides k - 5 + 5 = 6 + 5 k = 11 Proof : ( 1 / 2 ) ( k - 5 ) = ( 1 / 2 ) ( 11 - 5 ) = 6 / 2 = 3