# Posts by Akle

Total # Posts: 21

**Chemistry hw**

What is the answer for Tb and Tf??????? please help.

**Chemistry hw**

Assuming 100% dissociation, calculate the freezing point and boiling point of 3.13 m SnCl4(aq). Tf=? Tb=? My work: SnCl4 with 100% dissociation gives a van't hoff factor of 5, 1Sn 4+ ion and 4 Cl- ions deltaT = i x Kf x m for freezing point = 5 x 0.51C/m x 3.13m = deltaTf ...

**CHEMISTRY**

Thanks so much! :] I understand my mistake!

**CHEMISTRY**

A solution of H2SO4(aq) with a molal concentration of 1.94m has a density of 1.119g/mL. What is the molar concentration of this solution? I got an answer of 2.17 M and it is incorrect..please help. My work: So Molar concentration = molal concentration * density = 1.94 mol/kg...

**Chem**

Thank you! It did and i found my error a minute before you posted this. Once again, I always appreciate your help DrBob222 :)

**Chem**

DrBob222, I got an answer of 33 and 24.23 as the temperature but it is incorrect. I looked at your response to David and unfortunately it did not help me. Would you please take a look at this question and help me out. Thanks. If the heat from burning 5.800 g of C6H6 is added ...

**CHEM**

yeah i converted it. It was suppossed to be kj :]

**CHEM**

I got an answer of 56.976. The answer is negative though since the reaction is exothermic. Other than that great explanation. Thank you so much. You are the best!!!! :]

**CHEM**

This is my work..... (18g) (4.184 J)(28.70-24.07) I get 350.95 then i divide it by 0.0340 and get 10322.17. Then I divide it by a 1000 and get 10.322... It is wrong. Can you take a look at my work and tell me what i did wrong and confirm the right answer for me thanks!

**CHEM**

I know I posted this question again but no one is really helping me. Can someone please help me as soon as possible. In a constant-pressure calorimeter, 60.0 mL of 0.340 M Ba(OH)2 was added to 60.0 mL of 0.680 M HCl. The reaction caused the temperature of the solution to rise ...

**CHEM**

Yes! It is right. Thank you for your help. I really appreciate it.

**CHEM**

You can select more than one answer and I can't seem to figure it out.

**CHEM**

sorry i meant the second one. I put the second one and it marked me wrong. As well, I put the last two and it marked me wrong also.

**CHEM**

I think it is only the first one, but it marked me wrong.

**CHEM**

At constant pressure, which of these systems do work on the surroundings? Check all that apply. 2A (g) + B(s) --> 3C(g) 2A (g) +2B (g) -->5C(g) A(g)+ B(g) --> C(g) A (s) +2B(g)--> C(g)

**CHEM**

This is my work..... (18g) (4.184 J)(28.70-24.07) I get 350.95 then i divide it by 0.0340 and get 10322.17. Then I divide it by a 1000 and get 10.322... It is wrong. Can you take a look at my work and tell me what i did wrong and confirm the right answer for me thanks!

**CHEM**

Also can you look it up as well thanks. I really appreciate it!

**CHEM**

I solved it numerous times and it says I am getting the wrong answer. Could you help explain how to solve it and see what I am doing wrong please.

**CHEM**

In a constant-pressure calorimeter, 60.0 mL of 0.340 M Ba(OH)2 was added to 60.0 mL of 0.680 M HCl. The reaction caused the temperature of the solution to rise from 24.07 °C to 28.70 °C. If the solution has the same density and specific heat as water, what is ΔH ...

**CHEM**

I got an answer of 24.23 degrees celsius and it marked me wrong? Can someone please explain and tell me what they get.

**CHEM**

If the heat from burning 5.800 g of C6H6 is added to 5691 g of water at 21 °C, what is the final temperature of the water? 2C6H6(l) +15O2 (g)----> 12CO2(g)+6H2O(l) +6542