A sledder has 700 J of potential energy and 100 J of kinetic energy at one point on a steep hill. How much kinetic energy will the sledder have at the bottom of the hill? (Assume negligible air resistance and friction.)
what is 700+100J ?
To solve this problem, we can use the principle of conservation of mechanical energy, which states that the total mechanical energy of a system remains constant if no external forces are acting on it.
Given that the sledder has 700 J of potential energy and 100 J of kinetic energy at one point on the hill, the total mechanical energy is:
Total mechanical energy = Potential energy + Kinetic energy
= 700 J + 100 J
= 800 J
According to the conservation of mechanical energy, the total mechanical energy at any point on the hill should remain constant. So, the total mechanical energy at the bottom of the hill will also be 800 J.
At the bottom of the hill, all of the potential energy will be converted to kinetic energy, so the kinetic energy at the bottom will be 800 J.
Therefore, the sledder will have 800 J of kinetic energy at the bottom of the hill.
To solve this problem, we can use the principle of conservation of mechanical energy. According to this principle, the total mechanical energy of an object (sum of potential energy and kinetic energy) remains constant as long as there are no external forces acting on it.
Given that the sledder has 700 J of potential energy and 100 J of kinetic energy at one point on the hill, the total mechanical energy at that point is 800 J (700 J of potential energy + 100 J of kinetic energy).
Since there is no air resistance or friction, we can assume that the total mechanical energy remains constant throughout the sled ride. Therefore, the total mechanical energy at the bottom of the hill would also be 800 J.
At the bottom of the hill, all the potential energy is converted into kinetic energy. Therefore, the sledder will have 800 J of kinetic energy at the bottom of the hill.
So, the answer is 800 J of kinetic energy.