A corvette can go from 0~60 mph in 4.3 seconds. If the mass of the car is 1443 kg how much work is required to complete this task (assuming it is on a horizontal road)?
(1/2) m v^2/ time
once again
now try some yourself please.
Oh, I gave you the power
the work = energy = (1/2) m v^2
thxXD
V = 60mi/h * 1600m/mi * 1h/3600s = 26.7 m/s.
Work = 0.5M*V^2 Joules.
To find the work required to accelerate the car from 0 to 60 mph, we can use the principle of work-energy theorem. The work done on an object is equal to the change in its kinetic energy.
First, let's convert the velocity from mph to m/s. We know that 1 mph is equal to 0.447 m/s. So, 60 mph is equal to 26.8224 m/s.
Next, we can find the initial and final kinetic energy of the car:
Initial kinetic energy = 1/2 * mass * (initial velocity)^2
Final kinetic energy = 1/2 * mass * (final velocity)^2
Since the initial velocity is 0 m/s, the initial kinetic energy is 0. The final kinetic energy can be calculated as follows:
Final kinetic energy = 1/2 * 1443 kg * (26.8224 m/s)^2
Now, to find the work done, we subtract the initial kinetic energy from the final kinetic energy:
Work = Final kinetic energy - Initial kinetic energy
Therefore, the work required to accelerate the car from 0 to 60 mph is the same as the final kinetic energy:
Work = 1/2 * 1443 kg * (26.8224 m/s)^2
To calculate this value, simply substitute the values into the equation and solve:
Work = 1/2 * 1443 kg * (26.8224 m/s)^2
= 0.5 * 1443 kg * (26.8224 m/s)^2
= 54484.7 Joules
Therefore, approximately 54484.7 Joules of work is required to accelerate the Corvette from 0 to 60 mph.