Physics

posted by kt

A 0.25 kg ball moving at 19.0 m/s is hit by a bat. The ball leaves the bat at a speed of 38 m/s in the opposite direction. If the bat is in contact with the ball for 0.01 s, find the magnitude of the average force exerted on the ball by the bat.

  1. Anonymous

    force = change in momentum/ time
    change in momentum = .25 (38 - -19) = .25 (57)
    F = .25 (57) / 0.01 Newtons

  2. Henry

    V = Vo + a*t =-38.
    19 + a*0.01 = -38.
    a = ? It will be negative.

    F = M*a.

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