a mass of 100kg moves in a circular path of radius of 5cm with uniform speed of 20m/s.find the centripetal acceleration and centripetal force.
horizontal path?
acceleration=v^2/r=20^2/.05
force= mass*acceleration
But you have a typo I suspect. No way 100 kg is moving at any such speed at five cm. Maybe 5 m or 1 kg or something.
To find the centripetal acceleration and centripetal force for an object moving in a circular path, we can use the following formulas:
1. Centripetal acceleration (a):
The centripetal acceleration is given by the formula:
a = (v^2) / r,
where v is the speed of the object and r is the radius of the circular path.
2. Centripetal force (F):
The centripetal force is given by the formula:
F = (m * a),
where m is the mass of the object and a is the centripetal acceleration.
Let's calculate the centripetal acceleration first:
Given:
Mass (m) = 100 kg
Radius (r) = 5 cm = 0.05 m
Speed (v) = 20 m/s
Using the formula: a = (v^2) / r,
we substitute the values:
a = (20^2) / 0.05 = 40000 / 0.05 = 800000 m/s^2
Therefore, the centripetal acceleration is 800,000 m/s^2.
Now, let's calculate the centripetal force:
Using the formula: F = (m * a),
we substitute the values:
F = 100 kg * 800000 m/s^2 = 80000000 N
Therefore, the centripetal force is 80,000,000 N.
So, the centripetal acceleration is 800,000 m/s^2 and the centripetal force is 80,000,000 N.