A spring of force constant 1500nm-1 is acted upon by a constant force of 75n.calculate the potential energy stored in the spring (1)1.9j (2)3.2j (3)3.8j (4)5.0j.
This answer is complicated, this is not straight
force=kx
energy=1/2 k x^2=1/2 * k (force/k)^2==1/2 * 75^2/1500 joules one answer is good to two sig digits.
ARE YOU SURE THE ANSWER CORRECT
That answer is not straight .
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I don't known whether the answer is correct or not because it is clear
To calculate the potential energy stored in a spring, we can use the formula:
Potential Energy = (1/2) * k * x^2
where k is the force constant of the spring in Newtons per meter (N/m) and x is the displacement from the equilibrium position.
In this case, the force constant, k, is given as 1500 N/m. However, we don't have the displacement, x, explicitly given. Instead, we are given a constant force acting on the spring, which we can use to calculate the displacement using Hooke's Law.
Hooke's Law states that the force exerted by a spring is directly proportional to its displacement:
F = -k * x
where F is the force applied, k is the force constant, and x is the displacement.
In this case, we have a constant force of 75 N being applied to the spring. Plugging this into Hooke's Law:
75 = -1500 * x
Rearranging the equation:
x = -75 / -1500
x = 0.05 meters (or 5 cm)
Now that we have the displacement, we can calculate the potential energy using the formula:
Potential Energy = (1/2) * k * x^2
Potential Energy = (1/2) * 1500 * (0.05)^2
Potential Energy = 3.75 joules
Therefore, the potential energy stored in the spring is approximately 3.75 joules. So the closest option is (3)3.8j.