There were 4342 buttons in three bags, A, B and C. There were 18 more buttons in bag B than in bag A. There were 3 times as many buttons in bag C as in bag B. How many buttons were in bag A?
You're welcome.
X buttons in bag A,
x+18 buttons in bag B,
3(x+18) buttons in bag C.
x + (x+18) + 3(x+18) = 4342,
Russ/Victoria -- are you going to stick with Russ?
What don't you understand about my explanation?
A + A + 18 + 3(A + 18) = 4342
Thanks a lot for helping me solve the problem of
To determine the number of buttons in bag A, we can start by setting up equations based on the given information.
Let's say the number of buttons in bag A is 'x'.
According to the problem, there were 18 more buttons in bag B than in bag A. So, the number of buttons in bag B can be represented as 'x + 18'.
It is also mentioned that there were 3 times as many buttons in bag C as in bag B. Hence, the number of buttons in bag C can be expressed as '3 * (x + 18)'.
Now, we can calculate the total number of buttons by adding the number of buttons in each bag:
x + (x + 18) + 3 * (x + 18) = 4342
We can simplify this equation to:
x + x + 18 + 3x + 54 = 4342
5x + 72 = 4342
Next, we isolate the variable by subtracting 72 from both sides:
5x = 4270
Finally, we solve for x by dividing both sides of the equation by 5:
x = 854
Therefore, there were 854 buttons in bag A.