60% chocolates in a CADY chocolate box are round shaped and rest are square shaped.30% of the chocolates are in that box are both round shaped and has a peanut inside.Ryan bought a round shaped chocolate of CADY chocolate box from a shop.Then what is the probability that,the chocolate has a peanut inside?
If candies are only round-shaped, 30%.
If box contained both shapes, 60% * 30% = ?
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
To find the probability that the chocolate Ryan bought has a peanut inside, we need to consider the information given in the question.
Let's break down the information step by step:
1. We know that 60% of the chocolates in the CADY chocolate box are round shaped, and the rest are square shaped. This implies that the round-shaped chocolates make up 60% of the total number of chocolates in the box.
2. Additionally, we are told that 30% of the chocolates in the box are both round shaped and have a peanut inside. This means that 30% of the total number of chocolates in the box are round with peanuts.
Now, to calculate the probability that the chocolate Ryan bought has a peanut inside, we can use conditional probability by considering the fact that the chocolate is round shaped.
We need to find the probability that Ryan's chocolate has a peanut given that it is round shaped. This can be represented as:
P(Peanut | Round) = (P(Round ∩ Peanut)) / P(Round)
From the information given, we know that P(Round) = 60% or 0.6, and P(Round ∩ Peanut) = 30% or 0.3 (since this represents the percentage of chocolates that are both round and have peanuts).
Plugging these values into the formula, we get:
P(Peanut | Round) = 0.3 / 0.6 = 0.5
So the probability that the chocolate Ryan bought, being round shaped, has a peanut inside is 0.5 or 50%.