The following reactions is a first order reaction with respect to nitrite ion and its rate constant is 0.0030/s. In a solution that is 10.0 M NO2-, what is the half-life of the reaction?
NH4+ + NO2- -->N2 + 2H2O
See your questions/answers above.
To determine the half-life of a first-order reaction, you can use the equation:
t1/2 = (0.693 / k)
where:
t1/2 is the half-life of the reaction,
0.693 is the natural logarithm of 2, and
k is the rate constant for the reaction.
In this case, the rate constant (k) is given as 0.0030/s.
Simply plug the given value of k into the equation to find the half-life (t1/2):
t1/2 = (0.693 / 0.0030)
t1/2 = 231 s (rounded to three significant figures)
Therefore, the half-life of the reaction is 231 seconds.