What is the Concentration of 5.6 of grams of mg (OH)2 dissolves in 550ml
find the moles
... divide 5.6 by molar mass
divide moles by volume (usually in liters)
Please what is volume of a 0.100 mole per litre solution that contain 5.0 grams of Nacl
Molarity=moles/liters
.1mole=5.8grams NaCl in a liter
so volume= 1liter*5/5.8
To find the concentration of a solute in a solution, we need to calculate the molarity. Molarity is defined as the number of moles of solute per liter of solution.
Step 1: Convert the given mass of Mg(OH)2 to moles.
The molar mass of Mg(OH)2 is calculated by adding the atomic masses of each element:
Molar mass of Mg(OH)2 = (24.31 g/mol for Mg) + (16.00 g/mol for O) + (2 * 1.01 g/mol for H) = 58.33 g/mol
To convert grams to moles, divide the given mass by the molar mass:
Number of moles of Mg(OH)2 = 5.6 g / 58.33 g/mol = 0.096 moles
Step 2: Convert the given volume to liters.
The given volume is 550 mL. To convert milliliters to liters, divide the volume by 1000:
Volume in liters = 550 mL / 1000 mL/L = 0.55 L
Step 3: Calculate the molarity.
Molarity (M) is defined as moles of solute divided by liters of solution:
Molarity of Mg(OH)2 = 0.096 moles / 0.55 L ≈ 0.175 M
Therefore, the concentration of 5.6 grams of Mg(OH)2 dissolved in 550 mL is approximately 0.175 M.