83) If ax + y = 6 and be - y =2, what is (a + b)x?
(I got 8)
90)
Define the operation (symbol) for any two real numbers x and y such that x (symbol) y = x^2 -2y. What is the value of 6 (symbol) (2 symbol 3)?
( I got 40)
92) F(x) = 3/x
What is f(f(6) + f(4))?
(I got 12/5)
Very good, I agree with all your answers
Okay thank you
83) To find (a + b)x, we need to solve the given system of equations to find the values of x and y.
Given equations:
ax + y = 6 ---(1)
be - y = 2 ---(2)
First, let's solve equation (2) for y:
be - y = 2
y = be - 2
Now substitute the value of y into equation (1):
ax + be - 2 = 6
To simplify the equation, combine the x and constant terms:
ax + be = 8
Now, we have the equation ax + be = 8. Since we want to find (a + b)x, that means we need to find the coefficient of x.
So, the coefficient of x in the equation ax + be = 8 is a + b. Therefore, (a + b)x = 8.
Answer: (a + b)x = 8
90) The given operation is defined as x (symbol) y = x^2 - 2y.
To find the value of 6 (symbol) (2 symbol 3), we need to substitute the values of x = 6 and y = 2 (symbol) 3 into the operation and calculate the result.
Substituting the values:
6 (symbol) (2 symbol 3) = 6^2 - 2(2^2 - 2(3))
= 36 - 2(4) - 2(6)
= 36 - 8 - 12
= 16
Answer: 6 (symbol) (2 symbol 3) = 16
92) Given function: f(x) = 3/x
To find f(f(6) + f(4)), we need to evaluate the function at f(6) + f(4).
Substituting the values:
f(6) + f(4) = 3/6 + 3/4
= 1/2 + 3/4
= 2/4 + 3/4
= 5/4
Now, substitute the value of f(6) + f(4) into f(x):
f(f(6) + f(4)) = f(5/4)
= 3/(5/4)
= 3 * (4/5)
= 12/5
Answer: f(f(6) + f(4)) = 12/5