A 250 L sample of oxygen is collected over water, which has a pressure of 34mmHg. If the total pressure for the container is 760.0mmHg pressure. What is the pressure of the oxygen gas alone?
To find the pressure of the oxygen gas alone, we need to calculate the partial pressure of water vapor and subtract it from the total pressure of the container.
The partial pressure of water vapor (Pwater vapor) can be determined using Dalton's Law of partial pressures, which states that the total pressure in a mixture of gases is equal to the sum of the partial pressures of each gas.
We know that the total pressure of the container (Ptotal) is 760.0 mmHg, and the pressure of the water vapor (Pwater) is 34 mmHg.
Using Dalton's Law, we can calculate the pressure of the oxygen gas alone as follows:
Poxygen = Ptotal - Pwater
Poxygen = 760.0 mmHg - 34 mmHg
Poxygen = 726.0 mmHg
Therefore, the pressure of the oxygen gas alone is 726.0 mmHg.
what is 760-34 mmHg.
Pressure(O2)+pressure (H2O)=760mmHg