In a solution of 7.8 g of benzene (C6H6)and 46.0g toluene (C6H5CH3) is mixed together then,the molecular fraction of benzene is:
divide each by the molemass of each, to get the moles of each.
then, benzeneMolecularMass=molesBenzene/totalmoles
To find the molecular fraction of benzene in the solution, we need to calculate the moles of benzene and toluene first.
1. Calculate the moles of benzene:
- The molar mass of benzene (C6H6) = 12.01 g/mol (carbon) + 1.01 g/mol (hydrogen) * 6 = 78.11 g/mol.
- The moles of benzene = mass of benzene / molar mass of benzene = 7.8 g / 78.11 g/mol.
2. Calculate the moles of toluene:
- The molar mass of toluene (C6H5CH3) = (12.01 g/mol * 6) + (1.01 g/mol * 5) + (12.01 g/mol * 2) + (1.01 g/mol * 3) = 92.14 g/mol.
- The moles of toluene = mass of toluene / molar mass of toluene = 46.0 g / 92.14 g/mol.
3. Calculate the total moles of the solution:
- Total moles = moles of benzene + moles of toluene.
4. Calculate the molecular fraction of benzene:
- Molecular fraction of benzene = moles of benzene / total moles.
By following these steps and doing the calculations, you will be able to find the molecular fraction of benzene in the mixed solution.