A pulley system shows is use to raise a load of 600N through 8m. If the effiency I 90%. Calculate
a, machincal advantage
b. Workdone by the effort
c. Effort applied
we can not see how many blocks you have in your block and tackle system so all I cab]n do is part B
0.90 * work = 600 * 8
so
work = 6000 * 8/9 Joules = 5333 Joules
To calculate the values, we need to understand the concepts of mechanical advantage, work, and efficiency.
a) Mechanical Advantage:
Mechanical advantage represents the ratio of the load (resistance) to the effort applied in a pulley system. It is determined by dividing the load by the effort.
Formula: Mechanical Advantage (MA) = Load / Effort
b) Work:
Work done is the product of force and displacement. In this case, we need to find the work done by the effort to raise the load.
Formula: Work Done (W) = Force (Effort) * Distance
c) Effort applied:
Effort applied represents the force exerted by the person handling the pulley system.
Now let's calculate the values:
Given:
Load = 600N
Distance = 8m
Efficiency = 90% or 0.9 (as a decimal)
a) Mechanical Advantage:
MA = Load / Effort
600N / Effort = 0.9
Effort = 600N / 0.9
Effort = 666.67N
b) Work Done by the Effort:
W = Effort * Distance
W = 666.67N * 8m
W = 5333.36 Joules
c) Effort applied:
Effort = 666.67N (calculated in the first part)
Therefore:
a) Mechanical Advantage = 666.67N
b) Work Done by the Effort = 5333.36 Joules
c) Effort applied = 666.67N
Note: The efficiency of 90% is not used in these calculations. It represents the ratio of useful work output to the total work input and is related to energy losses in the system.