The amount of heat released when 2.8g of ethane is completely burnt in excess of oxygen is 200kj what will be the heat of combustion of ethane? Answer plz...
Answer plz. Nope.
if you want heat of combutstion in kj/mole, change 2.8g to moles
If you want heat of combutstion in kj/grams, divide.
To determine the heat of combustion of ethane, you can use the concept of molar mass and stoichiometry.
First, you need to calculate the moles of ethane burnt:
Molar mass of C2H6 (ethane) = 2 * atomic mass of carbon (C) + 6 * atomic mass of hydrogen (H)
= 2 * 12.01 g/mol + 6 * 1.008 g/mol
= 30.07 g/mol
Moles of ethane = Mass of ethane / Molar mass of ethane
= 2.8 g / 30.07 g/mol
Next, you can use the balanced equation for the combustion of ethane:
C2H6 + 7/2O2 -> 2CO2 + 3H2O
From the equation, you can see that 1 mole of ethane produces 2 moles of carbon dioxide (CO2) and 3 moles of water (H2O).
Now, you can calculate the number of moles of ethane burnt:
Moles of ethane burnt = Moles of ethane
Next, you can calculate the heat of combustion using the given heat released:
Heat released = Heat of combustion * Moles of ethane burnt
Rearranging the equation, the heat of combustion can be calculated as:
Heat of combustion = Heat released / Moles of ethane burnt
Plugging in the values:
Heat of combustion = 200 kJ / (2.8 g / 30.07 g/mol)
Simplifying:
Heat of combustion = 200 kJ / (2.8/30.07) mol
Finally, calculate the heat of combustion:
Heat of combustion ≈ 7,286.6 kJ/mol
Therefore, the approximate heat of combustion of ethane is 7,286.6 kJ/mol.