1.7g of sodium oxalate was dissolved in 250ml of distilled water. Calculate the molarity and normality of the solution
mols Na2C2O4 = grams/molar mass = ?
M = mols/L solution. L soln is 0.250 L.
0.0507
To calculate the molarity (M) and normality (N) of the solution, we first need to determine the number of moles of sodium oxalate (Na2C2O4) present in the solution.
Step 1: Convert grams to moles
Molar mass of sodium oxalate (Na2C2O4) = 2(22.99 g/mol) + 2(12.01 g/mol) + 4(16.00 g/mol) = 133.99 g/mol
Number of moles of sodium oxalate (Na2C2O4) = mass of sodium oxalate (g) / molar mass of sodium oxalate (g/mol)
Number of moles of sodium oxalate = 1.7 g / 133.99 g/mol
Step 2: Calculate molarity
Molarity (M) = moles of solute / volume of solution (in liters)
Volume of solution = 250 mL = 250/1000 L = 0.25 L (since 1 L = 1000 mL)
Molarity (M) = (1.7 g / 133.99 g/mol) / 0.25 L
Step 3: Calculate normality
Normality (N) = Molarity (M) × total equivalents
For sodium oxalate, each molecule has a total of 2 acid equivalents (2 H+ ions can be neutralized).
Total equivalents = 2 × moles of solute
Normality (N) = (1.7 g / 133.99 g/mol) × 2
Now, calculate the molarity and normality:
Molarity (M) = (1.7 g / 133.99 g/mol) / 0.25 L
Normality (N) = (1.7 g / 133.99 g/mol) × 2
To calculate the molarity and normality of the solution, we first need to determine the number of moles of sodium oxalate present in the solution.
Step 1: Calculate the number of moles of sodium oxalate
The molar mass of sodium oxalate (Na2C2O4) is:
2 * atomic mass of sodium (Na) + atomic mass of carbon (C) + 2 * atomic mass of oxygen (O)
= (2 * 22.99 g/mol) + 12.01 g/mol + (2 * 16.00 g/mol)
≈ 133.99 g/mol
Given that we have 1.7 g of sodium oxalate, we can calculate the number of moles using the formula:
moles = mass / molar mass
moles = 1.7 g / 133.99 g/mol
≈ 0.0127 mol
Step 2: Calculate the molarity
Molarity (M) is defined as the number of moles of solute per liter of solution.
molarity = moles / volume (in L)
Since the volume of the solution is given as 250 mL, we need to convert it to liters:
volume = 250 mL / 1000 mL/L
= 0.25 L
Now we can calculate the molarity:
molarity = 0.0127 mol / 0.25 L
= 0.051 M
Step 3: Calculate the normality
Normality (N) is a measure of the number of equivalents of the solute per liter of solution. In this case, sodium oxalate is a diprotic acid, which means that each mole of sodium oxalate can donate two equivalents of a reactive species.
normality = 2 * molarity
normality = 2 * 0.051 M
= 0.102 N
Therefore, the molarity of the solution is 0.051 M, and the normality of the solution is 0.102 N.