A plane flies northward for 430km, it then flies eastwards for 380km.How far is it from the starting point?
you have two sides of a right triangle ... the distance is the hypotenuse
a^2 + b^2 = c^2
solve it
c² =a² + b²
c² =430² + 380²
c²=184900 + 144400
c²=329300
square root both side
√c²=√329300
c=573.8466694
Approximately
c=574km
To find the distance from the starting point, we can use the Pythagorean theorem in a right-angled triangle formed by the Northward distance, Eastward distance, and the hypotenuse (the straight-line distance from the starting point to the final position of the plane).
The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
In this case, the Northward distance is 430 km and the Eastward distance is 380 km. We can label the Northward distance as side A, the Eastward distance as side B, and the hypotenuse as side C.
So, we need to calculate the value of C, which represents the distance from the starting point. We can use the formula:
C^2 = A^2 + B^2
Plugging in the values we have:
C^2 = 430^2 + 380^2
C^2 = 184,900 + 144,400
C^2 = 329,300
To find C, we take the square root of both sides:
C = √329,300
C ≈ 573.21 km
Therefore, the plane is approximately 573.21 km from the starting point.