Given that angle AXB is complementary to both angle CYD and angle FZE, and angle AXB = 4°, what is angle CYD + angle FZE?

We know that complementary angles add up to 90 degrees. Since angle AXB is complementary to angle CYD and angle FZE, we can say that:

angle AXB + angle CYD = 90 degrees (1)
angle AXB + angle FZE = 90 degrees (2)

Given that angle AXB is 4 degrees, we can substitute it into equations (1) and (2):

4 + angle CYD = 90 degrees (3)
4 + angle FZE = 90 degrees (4)

Now, we can solve equations (3) and (4) to find angle CYD and angle FZE respectively.

Subtracting 4 from both sides in equation (3), we have:
angle CYD = 90 - 4
angle CYD = 86 degrees

Subtracting 4 from both sides in equation (4), we have:
angle FZE = 90 - 4
angle FZE = 86 degrees

Therefore, angle CYD + angle FZE = 86 degrees + 86 degrees = 172 degrees.

To find the sum of angles CYD and FZE, we first need to find the measure of angle AXB.

Since angle AXB is complementary to both angle CYD and angle FZE, it means that the sum of angle AXB and angle CYD is equal to 90°, and the sum of angle AXB and angle FZE is also equal to 90°.

Given that angle AXB has a measure of 4°, we can subtract 4° from 90° to find the measure of angle CYD or FZE.

Measure of angle CYD = 90° - 4° = 86°

Similarly, measure of angle FZE = 90° - 4° = 86°

Therefore, the sum of angle CYD and angle FZE is:

angle CYD + angle FZE = 86° + 86° = 172°

So, angle CYD + angle FZE is 172°.

well, we know that AXB=4

AXB+CYD=90
So, both CYD and FZE = 86 and their sum is 172

thanks i got that, just checking