the mass of an empty container is measured and found to be 55.75g. the container is filled to thee rim with water. its mass is measured again and found to be 105.75g. The container is emptied and dried with paper towel to remove any traces of water. It is then filled with an unknown liquid., The new mass is 123.75g. Use calculations to determine if the unknown liquid is cooking oil or corn syrup.
WATER - 1.00 DENSITY (g/cm3
COOKING OIL - 0.894 Density (g/cm3
Corn syrup 1.36 density g/cm3
if u can help me solve this plz!
mass of water = 105.75 - 55.75 = 50 g
so volume of water = 50 g (1 cm^3/g) = 50 cm^3 = vol of bottle
mass of stuff = 123.75 - 55.75 = 68 g
density of stuff = 68 g /50 cm^3 = 1.36 g/cm^3
Thanks!
Sure, I'd be happy to assist you with this problem. Let's start by calculating the mass of water that filled the container.
Mass of water = Mass of filled container - Mass of empty container
Mass of water = 105.75g - 55.75g
Mass of water = 50g
Now, let's calculate the volume of water using its density.
Density of water = Mass of water / Volume of water
Since the density of water is 1.00 g/cm³, we can rearrange the equation to solve for the volume.
Volume of water = Mass of water / Density of water
Volume of water = 50g / 1.00 g/cm³
Volume of water = 50 cm³
Now, let's find the mass and volume of the unknown liquid.
Mass of unknown liquid = Mass of filled container - Mass of empty container
Mass of unknown liquid = 123.75g - 55.75g
Mass of unknown liquid = 68g
Volume of unknown liquid = Mass of unknown liquid / Density of unknown liquid
To determine if the unknown liquid is cooking oil or corn syrup, we can compare the calculated volume of the unknown liquid with the volumes of cooking oil and corn syrup for the given masses.
Volume of cooking oil = 68g / 0.894 g/cm³
Volume of cooking oil = 76.07 cm³
Volume of corn syrup = 68g / 1.36 g/cm³
Volume of corn syrup = 50 cm³
Comparing the volumes, since the volume of the unknown liquid (68 cm³) is closer to the volume of corn syrup (50 cm³), we can conclude that the unknown liquid is more likely to be corn syrup.
To determine if the unknown liquid in the container is cooking oil or corn syrup, we can use the concept of density. Density is defined as the mass of an object divided by its volume. Therefore, to find the volume of the liquid in the container, we need to subtract the mass of the empty container from the mass of the container filled with the liquid.
First, let's calculate the volume of water in the container:
Mass of water = Mass of filled container - Mass of empty container = 105.75 g - 55.75 g = 50 g
Since water has a density of 1.00 g/cm³, we can calculate the volume of water:
Volume of water = Mass of water / Density of water = 50 g / 1.00 g/cm³ = 50 cm³
Next, let's calculate the volume of the unknown liquid in the container:
Mass of unknown liquid = Mass of container with unknown liquid - Mass of empty container = 123.75 g - 55.75 g = 68 g
Now, we can calculate the density of the unknown liquid by dividing its mass by its volume:
Density of unknown liquid = Mass of unknown liquid / Volume of unknown liquid = 68 g / Volume of unknown liquid
To determine whether the unknown liquid is cooking oil or corn syrup, we can compare the calculated density of the unknown liquid to the known densities of cooking oil and corn syrup.
For cooking oil, its density is 0.894 g/cm³.
For corn syrup, its density is 1.36 g/cm³.
If the calculated density of the unknown liquid is approximately 0.894 g/cm³, then it is likely cooking oil.
If the calculated density of the unknown liquid is approximately 1.36 g/cm³, then it is likely corn syrup.
By substituting the appropriate value into the equation, we can determine if the unknown liquid is cooking oil or corn syrup.
no calculation needed.
The new liquid is heavier than the water.
Only one of the choices is heavier than water.
It would have been a better question if several heavier liquids had been offered.