Can someone help me make an equation for a horizontal eIIipse with major axis thats 50 units and minor axis thats 20 units?? Thanks so much in advance!!!!! im stuck :^(

major axis thats 50 units ---> a = 25

minor axis thats 20 units ---> b = 10

form the equation in standard form, it is just a matter of writing it down.

thanks!!! I know the formula for a horizontal ellipse so ive got it from here!!

Of course! I can help you with that.

To write an equation for a horizontal ellipse, we can start with the standard form of an ellipse equation:

(x-h)^2/a^2 + (y-k)^2/b^2 = 1

Where (h, k) is the center of the ellipse, "a" represents the length of the semi-major axis, and "b" represents the length of the semi-minor axis.

In your case, the length of the semi-major axis is 50 units and the length of the semi-minor axis is 20 units. Since the ellipse is horizontal, the center will be at (h, k).

Now, let's substitute these values into the equation:

(x-h)^2/50^2 + (y-k)^2/20^2 = 1

Since the ellipse is horizontal, the center will be at (h, k) = (0, 0). Plugging in these values, we get:

x^2/50^2 + y^2/20^2 = 1

And that's the equation of a horizontal ellipse with a major axis of 50 units and a minor axis of 20 units!