In astronomy the term perihelion refers to the point in the orbit of an asteroid, comet, or planet when it is closest to the sun. Aphelion refers to the point when the object is farthest away from the sun. research facts about the dwarf planet Ceres. calculate the average orbital speed of Ceres in miles/hour when it is closer to the sun and when it is further away

so, have you done any research yet?

To research facts about the dwarf planet Ceres, I would suggest visiting reliable astronomy websites, such as NASA's website or the International Astronomical Union's (IAU) website. These sources will provide accurate and up-to-date information about Ceres, including its size, composition, and orbital characteristics.

To calculate the average orbital speed of Ceres when it is closer to the Sun and when it is further away, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the orbital period (T) is proportional to the cube of the semi-major axis (a) of the orbit.

First, let's gather the necessary information:

1. Semi-major axis (a) of Ceres' orbit:
The semi-major axis is the average distance between Ceres and the Sun. According to NASA, Ceres has a semi-major axis of about 2.768 astronomical units (AU). 1 AU is approximately equal to the average distance between Earth and the Sun, which is about 93 million miles.

2. Orbital period (T) of Ceres:
The orbital period is the time it takes for Ceres to complete one orbit around the Sun. Ceres takes approximately 4.6 Earth years (or 1681.63 days) to complete its orbit.

Now we can use Kepler's Third Law to calculate the average orbital speed of Ceres when it is closer and when it is further away from the Sun.

1. When Ceres is closer to the Sun (perihelion):
Using Kepler's Third Law: T^2 = a^3
T = 1681.63 days (orbital period)
a = 2.768 AU (semi-major axis)

Converting the orbital period from days to hours:
1681.63 days * 24 hours/day = 40357.5 hours

Calculating the average orbital speed:
Solving for v (orbital speed):
v = (2 * π * a) / T

v = (2 * π * 2.768 AU * 93 million miles/AU) / 40357.5 hours

Using the value of π ≈ 3.1416:
v ≈ 18.156 million miles / 40357.5 hours
v ≈ 450.48 miles/hour (rounded to two decimal places)

2. When Ceres is further from the Sun (aphelion):
Using the same values for T and a, we can calculate the average orbital speed of Ceres when it is further from the Sun using the same formula:

v = (2 * π * 2.768 AU * 93 million miles/AU) / 40357.5 hours

v ≈ 450.48 miles/hour (rounded to two decimal places)

Therefore, the average orbital speed of Ceres remains approximately 450.48 miles/hour, regardless of whether it is closer or further from the Sun.