You’re driving along a straight road at a speed of 48.0 km/h when you see a deer in the road 35.0 m ahead of you. After applying the brakes it takes you 2.00 s to bring your car to rest, but there is a reaction time period (the time between when you first see the deer and when you first apply the brakes) during which the car continues to travel at 48.0 km/ h. The goal of this exercise is to answer the question: Assuming the acceleration is constant during the braking phase of the motion, what is the longest your reaction time can be if you are to stop the car before reaching the deer? Carry out parts (a) and (b) as described above. Note that there are two phases to the motion, a constant velocity phase and a constant-acceleration phase, so you should clearly separate the information for the two phases in your table. (c) Briefly describe the method you will use to solve the exercise. (d) Solve for your maximum possible reaction time

This problem lays out the solution in excruciating detail. What is it you dont understand?

To solve this exercise, let's break down the problem into three parts and use the following information:

Given:
- Initial velocity (v0) = 48.0 km/h
- Distance to the deer (d) = 35.0 m
- Braking time (tb) = 2.00 s

First, let's convert the initial velocity from km/h to m/s:

v0 = 48.0 km/h * (1000 m/1 km) * (1 h/3600 s)
v0 = 13.3 m/s

Now, let's calculate the distance covered during the reaction time period.

Part (a) - Constant Velocity Phase:
We need to find the distance covered during the reaction time at a constant velocity of 48.0 km/h.

During the reaction time (tr), the distance covered is given by:
d1 = v0 * tr

Part (b) - Constant Acceleration Phase:
After the reaction time, the car starts decelerating with constant acceleration to come to a stop.

Using the equation of motion:
v = v0 + at
where:
v = final velocity (0 m/s, since the car comes to a stop)
v0 = initial velocity (13.3 m/s)
a = acceleration
t = time required to reach from v0 to v

Given that v = 0 m/s, we can rearrange the equation to solve for time t:
t = (v - v0) / a

We can use this time t to calculate the additional distance covered during the constant acceleration phase:
d2 = v0 * t + (1/2) * a * t^2
where:
d2 = distance covered during the constant acceleration phase
a = acceleration
t = time calculated from the equation of motion

Part (c) - Method:
To find the maximum reaction time that allows you to stop the car before reaching the deer, we need to calculate the total distance covered during the reaction time period (d1) and the constant acceleration phase (d2). Then, we compare this total distance with the distance to the deer (d) to ensure it is less for a safe stop.

Part (d) - Solving for Maximum Reaction Time:
1. Calculate d1 using the equation d1 = v0 * tr.
2. Calculate t using the equation t = (v - v0) / a.
3. Calculate d2 using the equation d2 = v0 * t + (1/2) * a * t^2.
4. Calculate the total distance covered (d_total) by summing d1 and d2.
5. Compare d_total with the distance to the deer (d).
- If d_total < d, the reaction time is within the limit.
- If d_total >= d, the reaction time is too long to stop before reaching the deer.

By following this step-by-step process, you can solve for the maximum possible reaction time that allows you to stop the car before reaching the deer.