2. One +1.0 C (one coulomb) charge and another -1.0 C charge are located 1.0 m apart.
a. Calculate the magnitude of the electric force between them.
b. In what direction does the force act?
To calculate the magnitude of the electric force between two charges, we can use Coulomb's law. Coulomb's law states that the magnitude of the electric force between two charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them.
a. To calculate the magnitude of the electric force between the charges, we can use the following formula:
F = (k * |q1| * |q2|) / r^2
Where:
F is the electric force between the two charges,
k is the electrostatic constant, which has a value of approximately 8.99 x 10^9 Nm^2/C^2,
|q1| and |q2| are the magnitudes of the charges,
and r is the distance between the charges.
For this problem, we have |q1| = 1.0 C, |q2| = 1.0 C, and r = 1.0 m.
Plugging these values into the formula, we get:
F = (8.99 x 10^9 Nm^2/C^2 * 1.0 C * 1.0 C) / (1.0 m)^2
Simplifying this expression, we find:
F = 8.99 x 10^9 N
Therefore, the magnitude of the electric force between the charges is approximately 8.99 x 10^9 Newtons.
b. The direction of the force depends on the sign of the charges. Like charges (both positive or both negative) repel each other, while opposite charges attract each other. In this case, we have one positive charge and one negative charge, so the force will be attractive. The force will act along the line connecting the two charges, from the negative charge towards the positive charge.
a. To calculate the magnitude of the electric force between the charges, we can use Coulomb's Law:
F = (k * |q1 * q2|) / r^2)
Where:
- F is the magnitude of the electric force between the charges
- k is the electrostatic constant, approximately equal to 9 x 10^9 N·m^2/C^2
- |q1| and |q2| are the magnitudes of the charges (|1.0 C| = 1.0 C)
- r is the distance between the charges (1.0 m)
Let's substitute the values into the formula:
F = (9 x 10^9 N·m^2/C^2 * |1.0 C * -1.0 C|) / (1.0 m)^2
F = (9 x 10^9 N·m^2/C^2 * 1.0 C * 1.0 C) / 1.0 m^2
F = (9 x 10^9 N·m^2/C^2) / 1.0 m^2
F = 9 x 10^9 N
Therefore, the magnitude of the electric force between the charges is 9 x 10^9 N.
b. The force between two charges is always attractive if they have opposite signs. In this case, one charge is +1.0 C and the other is -1.0 C, so they have opposite signs. Therefore, the force between them will be attractive, pulling them towards each other.