Tanya wants to gift-wrap a container that is in the shape of a right circular cylinder. The radius and height of the container are given below in centimeters.

Radius is 2.1 cm.
Height is 8.8 cm.
Which estimate is closest to the minimum amounr of giftwrap Tanya needs to cover the entire container?
120 cm^2
132 cm^2 (My Answer)
432 cm^2
216 cm^2

two ends at pi*2.1^2 each is 27.71 cm^2

the curved side is 2 pi*2.1*8.8 = 116.11 cm^2

I agree with your answer, but it does not seem like quite enough.

Ignoring any overlap which you will obviously need, and ignoring any loss of paper ....

surface area = 2 circles + 1 rectangle
= 2(πr^2) + 2πrh
= 2(4.41π) + 4.2(8.8)π
= 143.82
I don't see that answer , the closest is your choice of 132, but that would not cover the can.
Poor choice of answers, unless there is a typo

Ok Thank You!

To calculate the minimum amount of gift wrap Tanya needs to cover the entire container, we need to find the lateral surface area of the right circular cylinder.

The lateral surface area of a right circular cylinder is given by the formula:

Lateral Surface Area = 2πrh

Where:
- π is approximately equal to 3.14 (a commonly used approximation of the mathematical constant pi)
- r is the radius of the cylinder
- h is the height of the cylinder

In this case, the radius is given as 2.1 cm and the height is given as 8.8 cm.

Let's calculate the lateral surface area:

Lateral Surface Area = 2 * 3.14 * 2.1 * 8.8
Lateral Surface Area = 116.736 cm^2

Since we are looking for the estimate closest to the minimum amount of gift wrap Tanya needs, we can round 116.736 to the nearest whole number.

Rounded Lateral Surface Area = 117 cm^2

Among the given options, the estimate closest to the minimum amount of gift wrap Tanya needs is 120 cm^2.