A 14.5 kg toy car is driving around a horizontal circular track with a period of 8.0 seconds. The radius of the circular track is 1.1 meters. What is the force of friction in Newtons between the car and the track that is necessary for the car to remain on the track?

how do i do this(get started or equation)

f = m v^2 / r

you have m and r , need to calculate v ... circumference / 8.0 s

To find the force of friction, we need to consider the centripetal force required to keep the car moving in a circular path. The centripetal force is provided by the friction between the car's tires and the track.

One way to find the force of friction is by using the following equation:

F_friction = (m * v^2) / r

Where:
F_friction is the force of friction
m is the mass of the car (14.5 kg in this case)
v is the velocity of the car
r is the radius of the circular track (1.1 meters in this case)

To find the velocity of the car, we can use the formula:

v = 2πr / T

Where:
v is the velocity of the car
r is the radius of the circular track (1.1 meters in this case)
T is the period of the car's motion (8.0 seconds in this case)

So, to get started, let's calculate the velocity of the car using the given values of radius and period. Then we can use this velocity along with the mass and radius to find the force of friction.