A 14.5 kg toy car is driving around a horizontal circular track with a period of 8.0 seconds. The radius of the circular track is 1.1 meters. What is the force of friction in Newtons between the car and the track that is necessary for the car to remain on the track?
Ac = v^2/R = R omega^2
every time.
To find the force of friction between the car and the track, we need to consider the centripetal force acting on the car.
The centripetal force is the force that keeps an object moving in a circular path. It is calculated using the following formula:
F = m * ((2 * pi * r) / T)^2
Where:
- F is the centripetal force
- m is the mass of the object (14.5 kg in this case)
- r is the radius of the circular track (1.1 meters)
- T is the period of the car (8.0 seconds)
Plug in the values into the formula:
F = 14.5 kg * ((2 * 3.14 * 1.1 m) / 8.0 s)^2
Calculating this expression will give us the value of the centripetal force exerted on the car. This force represents the minimum friction necessary for the car to remain on the track.