Sqr of 3c² over the sqr of 27 √ ̅3c² --------- √ ̅27 2. Simplify the radical √27 ∙ √3 3. Simplify the radical √ ̅75 - 4√ ̅75 4. Simplify the radical (√3 + √2)²
(√3 + √2)² well, (a+b)^2 = a^2 + 2 a b + b^2 so (√3 + √2)² = 3 + 2√6 + 2 = 5 + 2√6
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