The numerical value of the area of a square is 3 times it’s perimeter. What is the length of its side?

Explain please?

if the square has side s, then

perimeter = 4s
area = s^2

So, that means we have

s^2=3*4s
s^2=12s
s=12

Oh thank you.

To find the length of the side of the square, we need to set up an equation based on the given information.

Let's assume that the length of one side of the square is represented by 's'.

The perimeter of a square is calculated by adding up all four sides, so the perimeter would be 4s.

The area of a square is calculated by multiplying the length of one side by itself, so the area would be s * s or s^2.

Now, according to the given information, the numerical value of the area is 3 times its perimeter. Mathematically, we can express this as:

s^2 = 3 * 4s

To solve this equation, we can simplify it further:

s^2 = 12s

By subtracting 12s from both sides, we get:

s^2 - 12s = 0

Now, we can factorize the equation:

s(s - 12) = 0

From this equation, we can find two possible solutions:

1) s = 0
2) s - 12 = 0, which implies s = 12

Since the length of the side of a square cannot be zero, we can conclude that s = 12.

Therefore, the length of the side of the square is 12 units.