y= 3/x^3; [1,3]

Find the area under the graph of the function over the integral given. The book answer is 4/3

integral 3 x^-3 dx = 3 (-2) x^-2 = -6/x^2 at 3 - at 1

= -6/9 + 6/1 = -2/3 +18/3 = 16/3