Humid breaks down chs molecules become ionized) in an electric field of 3.0×10^6N/C. In that field what is the magnitude of the elextrostatisc force on(a) an electron
To find the magnitude of the electrostatic force on an electron in an electric field, we can use Coulomb's law. Coulomb's law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
The formula for the magnitude of the electrostatic force (F) on an object is given by:
F = q * E
Where:
F is the magnitude of the electrostatic force,
q is the charge of the object, and
E is the electric field strength.
In this case, we are looking for the magnitude of the electrostatic force on an electron. The charge of an electron is represented as -e, where e is the elementary charge (-1.6 x 10^-19 C).
Given:
Electric field strength (E) = 3.0 x 10^6 N/C
Charge of an electron (q) = -1.6 x 10^-19 C
Substituting the values into the formula, we have:
F = (-1.6 x 10^-19 C) * (3.0 x 10^6 N/C)
Calculating the product, we get:
F = -4.8 x 10^-13 N
The magnitude of the electrostatic force on an electron in this electric field is approximately 4.8 x 10^-13 Newtons.