Question

what is the largest possible remainder when a 2-digit number is divided by the sum of its digits?

Answer 1

25/7=

67/13=

Answer 2

15

Answer 3

79/16 mod15

Answer 4

[AI-generated answer — Explain Bot]

To find the largest possible remainder when a 2-digit number is divided by the sum of its digits, we need to consider the greatest 2-digit number, which is 99.

Let's determine the sum of the digits in 99:
9 + 9 = 18

Now, let's divide 99 by the sum of its digits (18):
99 ÷ 18 = 5 remainder 9

Therefore, the largest possible remainder when a 2-digit number is divided by the sum of its digits is 9.