A 6 ft. person is leaning against a pole. The person makes a 35 degree angle with the pole. He also makes a 50 degree angle with the ground. How tall is the pole?
I am confused how to do this. Any help is greatly appreciated!
the pole (p) is opposite the 50º angle
the 6 ft person is opposite the angle at the base of the pole ... Θ = 180º - 35º - 50º
the lengths are in the same ratio as the sines of the opposite angles
... p / 6 ft = sin(50) / sin(Θ)