what is the structure of a saturated molecule with 6 carbons and only hydrogens?
Would it just be 6 carbons in a row then CH3-CH2-CH2-CH2-CH2-CH3? I confused because it says saturated, what changes, how will it look?
What is the structure of a poly-unsaturated molecule with 6 carbon and only hydrogens?
What you have written is n-hexane. That is a saturated hydrocarbon. It is saturated if it has no double or triple bonds. There are isomers of n-hexane and those are saturated also.
To determine the structure of a saturated molecule with 6 carbons and only hydrogens, you need to understand the concept of saturation. In organic chemistry, saturation refers to the presence of single bonds between carbon atoms in a molecule. A saturated molecule has the maximum number of hydrogen atoms attached to its carbon atoms, meaning each carbon atom forms four single bonds, either with other carbon atoms or with hydrogen atoms.
For a saturated molecule with 6 carbons, you can imagine a straight chain of carbon atoms with hydrogen atoms attached to each carbon. In this case, with 6 carbons, the structure would be CH3-CH2-CH2-CH2-CH2-CH3. Each "CH2" represents a carbon with two hydrogens attached, and the "CH3" represents end carbon with three hydrogens attached.
Now, let's move on to a polyunsaturated molecule. Polyunsaturated molecules contain multiple double or triple bonds between carbon atoms, which results in fewer hydrogens attached to the carbon atoms compared to a saturated molecule. In this case, we have a polyunsaturated molecule with 6 carbons and only hydrogens.
To construct a polyunsaturated molecule with 6 carbons, you need to introduce double or triple bonds between carbon atoms. You can start with the saturated molecule structure we discussed earlier (CH3-CH2-CH2-CH2-CH2-CH3) and choose two carbon atoms to form a double bond between them. The specific placement of the double bond(s) will determine the structure of the polyunsaturated molecule. For example, you could introduce a double bond between the third and fourth carbon atoms, resulting in CH3-CH2-CH=CH-CH2-CH3. This is just one possible arrangement; there are other variations depending on where you place the double bonds.
Remember, in a polyunsaturated molecule, the number of hydrogens attached to the carbon atoms will be lower compared to the corresponding saturated molecule because the double or triple bonds reduce the number of available bonding sites for hydrogen atoms.