A 1.50 kg sample of a metal sample absorbs 43.5 kJ of heat, resulting in a
Temperature rise of 65.0 °C. What is the specific heat capacity of the metal?
M=1.50kG
Q=43.5kJ
dT=65C
q= mass x specific heat x delta T.
I don't know what units you want sp.h. in but I would convert kJ to J and kg to g. That way sp.h. comes out in J/g*C and you can convert to whatever you want.
Thanks bob that was my problem
To find the specific heat capacity of the metal, we need to use the formula:
q = mcΔT
where:
q is the heat absorbed or released by the object (in Joules),
m is the mass of the object (in kilograms),
c is the specific heat capacity of the object (in J/kg°C),
ΔT is the change in temperature (in °C).
Here's how we can calculate it:
Step 1: Convert the given quantities to SI units.
Mass: Given as 1.50 kg. No conversion needed.
Heat (q): Given as 43.5 kJ. Convert to Joules by multiplying by 1000.
43.5 kJ = 43.5 × 1000 J = 43500 J.
Change in temperature (ΔT): Given as 65.0 °C. No conversion needed.
Step 2: Plug the values into the formula and solve for c.
43500 J = 1.50 kg × c × 65.0 °C
Step 3: Rearrange the formula to solve for c.
c = (43500 J) / (1.50 kg × 65.0 °C)
Step 4: Calculate the specific heat capacity.
c = 43500 J / (97.5 kg°C)
c ≈ 446.15 J/kg°C
Therefore, the specific heat capacity of the metal is approximately 446.15 J/kg°C.