Calculate the volume (in mL) of a 0.150 M KCl(aq) solution that contains 10.00 g KCl
So I did 10/74.55 to get 0.13414 then /0.150 X 1000 = 894.254mL
find moles of KCl ... 10.00 g / molar mass
volume = moles KCl / 0.150 ... multiply by 1000 for mL
To calculate the volume of the solution, we first need to convert the mass of KCl into moles. Then, using the molarity of the solution, we can find the volume.
1. Calculate the moles of KCl:
- The molar mass of KCl is 74.5513 g/mol (39.0983 g/mol for potassium + 35.453 g/mol for chlorine).
- Divide the mass of KCl given (10.00 g) by the molar mass to find the moles of KCl:
10.00 g KCl / 74.5513 g/mol = 0.134 mol KCl
2. Use the molarity to find the volume of the solution:
- The molarity is given as 0.150 M, which means there are 0.150 moles of KCl per liter of solution.
- Divide the moles of KCl (0.134 mol) by the molarity (0.150 mol/L) to find the volume of the solution in liters:
0.134 mol / 0.150 mol/L = 0.893 L
3. Convert the volume from liters to milliliters:
- Multiply the volume in liters (0.893 L) by 1000 to convert it to milliliters:
0.893 L × 1000 mL/L = 893 mL
Therefore, the volume of the 0.150 M KCl(aq) solution that contains 10.00 g KCl is 893 mL.
To calculate the volume of the 0.150 M KCl(aq) solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, we need to calculate the number of moles of KCl using its molar mass:
Molar mass of KCl = atomic mass of K + atomic mass of Cl = 39.10 g/mol + 35.45 g/mol = 74.55 g/mol
Now, we can calculate the number of moles of KCl:
moles of KCl = mass of KCl / molar mass of KCl = 10.00 g / 74.55 g/mol = 0.134 moles
Next, we can use the formula for molarity to find the volume of the solution:
Molarity = 0.150 M = 0.134 moles / volume of solution (in liters)
Rearranging the equation, we find:
volume of solution (in liters) = moles of solute / Molarity
= 0.134 moles / 0.150 M
= 0.893 L
Finally, we need to convert the volume from liters to milliliters:
volume of solution (in mL) = volume of solution (in liters) * 1000 mL/L
= 0.893 L * 1000 mL/L
= 893 mL
Therefore, the volume of the 0.150 M KCl(aq) solution that contains 10.00 g KCl is 893 mL.