if from 10 moles NH3 and 5moles of H2SO4 all hte H-atoms are removed in order to from H2 gas, then find the no. of H2 molecules formed

30 moles H from NH3 ... 10 moles H from H2SO4

40 moles H yields ? moles H2

To find the number of H2 molecules formed, we can determine the limiting reactant in the reaction between NH3 and H2SO4. The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product that can be formed.

First, we need to determine the number of H-atoms present in the given moles of NH3 and H2SO4.

In NH3, we have:

- 3 moles of H-atoms per 1 mole of NH3.

Hence, from 10 moles of NH3, we have:

- 10 moles NH3 * 3 moles H-atoms/mole NH3 = 30 moles H-atoms.

In H2SO4, we have:

- 2 moles of H-atoms per 1 mole of H2SO4.

Hence, from 5 moles of H2SO4, we have:

- 5 moles H2SO4 * 2 moles H-atoms/mole H2SO4 = 10 moles H-atoms.

Now, we compare the number of H-atoms from both reactants. We see that the H2SO4 has fewer H-atoms than NH3. This means H2SO4 is the limiting reactant.

Since 1 mole of H2 has 2 moles of H-atoms, from 10 moles of H-atoms in H2SO4, we can expect to obtain:

- 10 moles H-atoms / 2 moles H-atoms per mole H2 = 5 moles of H2.

Now, to find the number of H2 molecules formed, we multiply the number of moles of H2 by Avogadro's number (6.022 x 10^23 molecules/mol):

- 5 moles H2 * (6.022 x 10^23 molecules/mol) = 3.011 x 10^24 H2 molecules.

Therefore, the number of H2 molecules formed is 3.011 x 10^24.