Physics

posted by A.S

The largest stable nucleus has a nucleon number of 209, and the smallest has a nucleon number of 1. If each nucleus is assumed to be a sphere, what is the ratio (largest/smallest) of the surface areas of these spheres? (Area209/Area1)

Please help!! I have a quiz due!!

Thanks

  1. scott

    sphere volume ... 4/3 π r^3

    surface area ... 4 π r^2

    s.a. = k v^(2/3)

    Area209 / Area1 = k[209^(2/3)] / k[1^(2/3)] = 209^(2/3)

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