posted by A.S
The largest stable nucleus has a nucleon number of 209, and the smallest has a nucleon number of 1. If each nucleus is assumed to be a sphere, what is the ratio (largest/smallest) of the surface areas of these spheres? (Area209/Area1)
Please help!! I have a quiz due!!
sphere volume ... 4/3 π r^3
surface area ... 4 π r^2
s.a. = k v^(2/3)
Area209 / Area1 = k[209^(2/3)] / k[1^(2/3)] = 209^(2/3)