At 65C,a sample of ammonia gas exerts a pressure of 10.2 atm..Calculate the pressure when the volume of gas is reduced to one tenth of the original value at the same temperature.Assume ammonia gas is an ideal gas
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of an ideal gas are inversely proportional when the temperature remains constant.
Boyle's Law can be expressed as:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
In this case, we are given the initial pressure (P1 = 10.2 atm) and the initial volume (V1). We need to calculate the final pressure (P2) when the volume is reduced to one-tenth of the original value (V2 = V1/10).
To find the final pressure, we can rearrange Boyle's Law equation:
P2 = (P1 * V1) / V2
Let's substitute the given values and calculate the final pressure.
P2 = (10.2 atm * V1) / (V1/10)
= (10.2 atm * V1) * (10/V1)
= 102 atm
Therefore, the pressure when the volume of the ammonia gas is reduced to one-tenth of the original value at the same temperature is 102 atm.