To play a game you spin a spinner like the one shown. You win if the arrow lands in one of the areas marked "WIN". Lee played this game many times and recorded her results. She won 8 times and lost 40 times. Use Lee's data to explain how to find the experimental probability of winning the game.

I am a bit lost on this math problem. Can you please explain this?

Hello I believe I got this one and understand this a bit better.

Win: 8/48=1/6

Lose: 40/48=5/6

8/40 = 1/5

Hello Ms. Sue I put 48 instead of 40 because there are a total of 48 times or 48 trials

Correct!

WIN = 8/48
= 1/6 or 0.1667 = 16.67% chance of winning

LOSE = 40/48
= 5/6 or 0.8333 = 83.33% chance of losing.

Thank you for checking my answer. I went back and reread it again like 4 or 5 times.

Your welcome, Patrick!

Of course! To find the experimental probability of winning the game, we can use Lee's data to determine the ratio of times she won to the total number of times she played.

In this case, Lee won 8 times and lost 40 times, so the total number of times she played the game would be 8 + 40 = 48.

To find the experimental probability of winning, we divide the number of times Lee won by the total number of times she played:

Experimental Probability of Winning = Number of Times Won / Total Number of Plays

Substituting the values, we have:

Experimental Probability of Winning = 8 / 48

Simplifying this fraction, we get:

Experimental Probability of Winning = 1 / 6

So the experimental probability of winning the game, based on Lee's data, is 1/6.

Keep in mind that this is the experimental probability, which is based on actual data collected from experiments or observations. It may not represent the true probability of winning the game in the long run, as it is based on a limited number of trials.