Hi! Could someone help me with this problem.

You have 8L feet of fence to make a rectangular vegetable garden alongside the wall of your house, where L is a positive constant. The wall of the house bounds one side of the vegetable garden. What is the largest possible area for the vegetable garden?

I am really confused with the 8L, saying that L is a positive constant. I tried doing the exercise ignoring the L and solving it like a normal optimization problem I am not getting a correct answer. I also tried putting the L by the answer and it is not taking either. Any help would be greatly appreciated.
Thank You!

see your earlier post. The area is 8L^2

Or, show your work so we can figure out where you went wrong.

Sure! I'd be happy to help you with this problem. To find the largest possible area for the vegetable garden, we need to optimize the rectangle's dimensions given the constraint of the 8L feet of fence and the fact that L is a positive constant.

Let's break down the problem step by step:

1. Define the variables:
- Let L be the length of the rectangle.
- Let W be the width of the rectangle.

2. Express the constraint:
- The perimeter of the rectangle must equal 8L since we have 8L feet of fence.
- The perimeter of a rectangle is given by the formula: P = 2L + 2W.
- Therefore, 2L + 2W = 8L.

3. Simplify the constraint:
- Divide both sides of the equation by 2 to simplify it: L + W = 4L.

4. Solve the constraint for W in terms of L:
- Subtract L from both sides of the equation: W = 4L - L = 3L.

5. Express the area of the rectangle:
- The area of a rectangle is given by the formula: A = L * W.

6. Substitute the value of W from the constraint into the area equation:
- Substitute W = 3L into A = L * W: A = L * (3L) = 3L^2.

Now we have the area of the rectangle, A, expressed in terms of L. To find the largest possible area, we need to maximize A.

7. Maximize the area by finding the critical points:
- Take the derivative of A with respect to L: dA/dL = 6L.
- Set the derivative equal to 0 to find the critical point: 6L = 0.
- Since L is a positive constant, the derivative is never equal to 0. So, there are no critical points.

8. Determine the behavior of the function:
- Since there are no critical points, we need to consider the endpoints of possible values for L.
- Since L is a positive constant, we do not have any endpoints to consider.

9. Conclusion:
- Since we have no critical points or endpoints to consider, we cannot determine a maximum area for the vegetable garden.
- The largest possible area is infinite.

I hope this explanation helps! Let me know if you have any further questions.