There were 56 more ducks than chicken on a farm. After 1/3 of the chickens and 4/5 of the ducks were sold, there was an equal number of chickens and ducks left on the farm. How many ducks were there on the farm at first?

Question

There were 56 more ducks than chicken on a farm. After 1/3 of the chickens and 4/5 of the ducks were sold, there was an equal number of chickens and ducks left on the farm. How many ducks were there on the farm at first?

Answer 1

d = c + 56

d / 5 = 2/3 c

multiplying by 15 (LCD) ... 3 d = 10 c

substituting ... 3 (c + 56) = 10 c ... 3c + 168 = 10 c

solve for c , then substitute back to find d