2CO + O2 → 2CO2
If 3.4 moles of carbon dioxide (CO2) form at the end of the reaction, how many moles of carbon monoxide (CO) and oxygen gas (O2) entered the reaction?
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3.4 moles of carbon monoxide and 1.7 moles of oxygen gas
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In order to determine the number of moles of carbon monoxide (CO) and oxygen gas (O2) that entered the reaction, we need to use the balanced chemical equation and the concept of mole ratios.
First, let's take a look at the balanced chemical equation:
2CO + O2 → 2CO2
From the equation, we can see that for every 2 moles of carbon monoxide (CO) reacting, we will produce 2 moles of carbon dioxide (CO2). Similarly, for every 1 mole of oxygen gas (O2) reacting, we will also produce 2 moles of carbon dioxide (CO2).
Now, let's solve the problem step by step:
1. Determine the moles of carbon dioxide (CO2) formed:
The given information states that 3.4 moles of carbon dioxide (CO2) are formed at the end of the reaction.
2. Use the mole ratio from the balanced equation:
Since the mole ratio between carbon monoxide (CO) and carbon dioxide (CO2) is 2:2, we can conclude that the number of moles of carbon monoxide (CO) formed is also 3.4 moles.
3. Calculate the moles of oxygen gas (O2) using the mole ratio:
Since the mole ratio between oxygen gas (O2) and carbon dioxide (CO2) is 1:2, we can calculate the moles of oxygen gas (O2) as follows:
Moles of oxygen gas (O2) = 1/2 * moles of carbon dioxide (CO2)
Moles of oxygen gas (O2) = 1/2 * 3.4 = 1.7 moles
Therefore, based on the given information and the balanced chemical equation, we can conclude that 3.4 moles of carbon monoxide (CO) and 1.7 moles of oxygen gas (O2) entered the reaction.
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according to the reaction equation
CO and CO2 are the same number of moles , O2 is half of CO2