Use place value to solve Pablo has a piece of wire that is 0.08 Meters long. Beth has a piece of wire that is 10 times as long as Pablo's wire.Li's wire is 1/10 as long as Pablo's wire. How long is Beth's wire? How long is Li's wire?
Pablo ---- .08 m
Beth ---- 10(.08) = .8 m
Li's ---- (1/10)(.08) = .008 m
To solve this problem using place value, we need to understand the relationship between the given measurements.
First, let's examine the value of Pablo's wire, which is 0.08 meters. The digit 0 is in the hundredths place, and the digit 8 is in the thousandths place. This means that Pablo's wire is eight hundredths of a meter long.
Beth's wire, on the other hand, is described as being 10 times as long as Pablo's wire. To find the length of Beth's wire, we need to multiply the length of Pablo's wire by 10. Therefore, Beth's wire is 0.08 meters × 10 = 0.8 meters long.
Li's wire is stated as being 1/10 as long as Pablo's wire. To calculate the length of Li's wire, we need to multiply the length of Pablo's wire by 1/10. This gives us Li's wire length as 0.08 meters × 1/10 = 0.008 meters.
Therefore, the length of Beth's wire is 0.8 meters, and the length of Li's wire is 0.008 meters.