Could someone please help me start this problem?
The following reaction occurs 1.000 atmosphere & 298.0 K.
CH3OH (l) + 3/2 O2 (g) → CO2 (g)+ 2H2O (l)
50.00 g of CH3OH, and excess oxygen. Calculate ΔU using ΔU = ΔH - PΔV
Calcuate dH with dHrxn = (n*dHo products) - (dHo reactants) and dH will be in kJ/mol. Then convert 50.0 g CH3OH to mols and calculate dH for the 50.0 grams.
Then calculate mols O2 initially and find the volume at the conditions listed, do the same for CO2 gas, find the difference and that is delta V. Then substitute and solve. Watch the sign on work.
I got -1133.40 for the delta H and -19.07 for the change in volume, then put them in the equation.
To calculate ΔU for the given reaction, where ΔU is the change in internal energy, we need to follow a few steps:
Step 1: Find the moles of CH3OH
Given the mass of CH3OH (50.00 g) and its molar mass, we can calculate the number of moles of CH3OH. The molar mass of CH3OH is approximately 32.04 g/mol.
moles of CH3OH = mass of CH3OH / molar mass of CH3OH
Step 2: Calculate the enthalpy change (ΔH)
You will need to find the enthalpy change for the reaction, which can be found in a thermochemical table. Let's say the ΔH for this reaction is -300 kJ.
Step 3: Determine the change in volume (ΔV)
The change in volume (ΔV) in this case is the change in the number of moles of gaseous species between the reactants and products. We can determine this by comparing the stoichiometric coefficients of the reactants and products.
In this case, comparing the coefficients of O2 and CO2 will give us the change in moles:
Δn(O2) = coefficient of O2 in the products - coefficient of O2 in the reactants = 0 - (3/2) = -3/2
Δn(CO2) = coefficient of CO2 in the products - coefficient of CO2 in the reactants = 1 - 0 = 1
ΔV = Δn(CO2) + (3/2) Δn(O2)
Step 4: Calculate ΔU using the given formula
Substitute the values you calculated into the formula ΔU = ΔH - PΔV.
Where P is the pressure in atmospheres and ΔV is the change in volume.
Given that the pressure is 1.000 atmosphere, you can calculate the final answer.