A bowling ball is rolling along a table with a constant velocity of 0.7 m/s. The table top is 1.1 meters (H) from the ground in height. Determine the horizontal range of the bowling ball as it falls to the floor. In other words, how far from the edge of the table top will the ball land on the floor?

find the time it takes to fall 1.1 m

find the horizonal distnace it goes in that time

again and again the same question !

I told you how to do the cannonball.

To determine the horizontal range of the bowling ball as it falls to the floor, we need to consider the horizontal motion and the vertical motion separately.

First, let's calculate the time it takes for the ball to reach the ground. We can use the equation for vertical motion:

h = (1/2) * g * t^2

Where:
h = Height of the table top (1.1 meters)
g = Acceleration due to gravity (approximately 9.8 m/s^2)
t = Time

Plugging in the values:
1.1 = (1/2) * 9.8 * t^2

Rearranging the equation:
t^2 = (2 * h) / g

Simplifying:
t^2 = (2 * 1.1) / 9.8
t^2 = 0.2245
t ≈ 0.47 seconds

Now that we know the time it takes for the ball to reach the ground, we can determine the horizontal range. Since the ball is rolling along the table with a constant velocity of 0.7 m/s, we can use the formula:

range = velocity * time

Plugging in the values:
range = 0.7 * 0.47
range ≈ 0.329 meters

Therefore, the ball will land approximately 0.329 meters away from the edge of the table top.