Ms. Pacheco, Mr. Edwards, and Mr. Richards are three math teachers at Turner Middle School. Ms. Pacheco is three years older than Mr. Richards. Mr. Edwards is twice as old as Mr. Richards. The sum of Mr. Richards’ age and Mr. Edwards’ age is 81. How old is each person?
Ms. Pacheco= R+3 Mr. Edwards = 2 (R) Mr. Richards = ??
Let R= Mr. Richards age
R+ 2 (R)= 81 (The total of Mr. Edwards & Mr. Richards)
R+R+R= 81 3R = 81 (divide both sides to 3)
It would look like: R = 27
The age of Ms. Pacheco is 30 (27+3= 30),
Mr. Edward's age is 54 (2 x 27= 54),
and Mr. Richards is 27.
Btw I have this problem for homework, but it's pretty easy :)
P = R + 3
E = 2 R
R + E = 81 ... R + 2 R = 81 ... R = ?
substitute back to find E and P
To solve this problem, we can use algebraic equations. Let's assign variables to each person's age:
Let Mr. Richards' age be x.
Ms. Pacheco is three years older than Mr. Richards, so her age is x + 3.
And Mr. Edwards is twice as old as Mr. Richards, so his age is 2x.
Now, we can set up equations based on the information given.
The sum of Mr. Richards' age and Mr. Edwards' age is 81:
x + 2x = 81
Combining like terms, we get:
3x = 81
To solve for x, we divide both sides of the equation by 3:
x = 27
So, Mr. Richards is 27 years old.
Now, we can substitute this value back into the other equations to find the ages of Ms. Pacheco and Mr. Edwards:
Ms. Pacheco's age: x + 3 = 27 + 3 = 30
Mr. Edwards's age: 2x = 2 * 27 = 54
Therefore, Ms. Pacheco is 30 years old, Mr. Edwards is 54 years old, and Mr. Richards is 27 years old.
23
Ms. Pacheco is 29, Mr. Richards is 26 and Mr. Edwards is 52.
P = R + 3E = 2 R
R + E = 81
R+