Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on the box?

To calculate the work done by Roger on the box, we need to use the formula:

Work = Force × Distance × cos(θ)

Where:
- Work is the amount of work done on the box
- Force is the applied force by Roger (60 newtons)
- Distance is the displacement of the box along the incline (10 meters)
- θ (theta) is the angle between the force and the direction of displacement (30° in this case)

First, let's calculate the cosine of the angle θ:

cos(θ) = cos(30°) ≈ 0.866

Now, we can substitute the values into the formula:

Work = 60 newtons × 10 meters × 0.866

Calculating the above equation gives us:

Work ≈ 519.6 Joules

Therefore, Roger will do approximately 519.6 Joules of work on the box.

at constant velocity? or is it increasing velociy?

Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on the box?

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