Complete and balance the molecular equation, including phases, for the reaction of aqueous sodium sulfate, Na2SO4, and aqueous barium nitrate, Ba(NO3)2.
I don't know how to do this please help
would the answer be
Ba2SO4^2+Na(NO3)2^2
No. I may be mistaken but I think you are changing the subscripts to make the equation balance. That is not allowed. YOu may change ONLY the coefficients.
You do form BaSO4 and NaNO3.
The valence of Ba is +2 and valence of sulfate is -2 so the formula is BaSO4. For NaNO3 the Na is +1 and the NO3^- polyatomic ion is -1 so the formula is NaNO3. Knowing the correct formulas try balancing change only the coefficients.
To complete and balance the molecular equation for the reaction between aqueous sodium sulfate (Na2SO4) and aqueous barium nitrate (Ba(NO3)2), you need to follow a few steps:
Step 1: Write the chemical equations for the dissociation of the reactants.
Na2SO4(aq) → 2Na+(aq) + SO4^2-(aq)
Ba(NO3)2(aq) → Ba^2+(aq) + 2NO3^-(aq)
Step 2: Identify the possible products based on the ions present in the dissociated forms.
The cations from Na2SO4 are Na+ and the anion is SO4^2-. The cations from Ba(NO3)2 is Ba^2+, and the anion is NO3^-. Therefore, the possible products are NaNO3(aq) and BaSO4(s).
Step 3: Write the molecular equation by combining the reactants and the products.
Na2SO4(aq) + Ba(NO3)2(aq) → NaNO3(aq) + BaSO4(s)
Step 4: Balance the equation by ensuring the same number of atoms on both sides.
Na2SO4(aq) + Ba(NO3)2(aq) → 2NaNO3(aq) + BaSO4(s)
Therefore, the balanced molecular equation is:
Na2SO4(aq) + Ba(NO3)2(aq) → 2NaNO3(aq) + BaSO4(s)